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V125BC [204]
3 years ago
7

Which is true for every atom of an element?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
6 0

C. It has mass and volume

Explanation:

Every atom of an element has mass and volume. Mass is the amount of substance it contains this is usually a function of their subatomic particles.

The bulk of the mass of an atom is concentrated in the nucleus where we have protons and neutrons. Electrons do not really add much to the mass of an atom.

Atoms also have specific volume.

  • The reason for our selection is that atoms are the smallest particle of matter.
  • Matter is anything that has weight and occupies space.
  • Since it is matter, it must have specific weight and volume

learn more:

Matter brainly.com/question/8839455

#learnwithBrainly

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Which of the following forms a molecular solid? Which of the following forms a molecular solid? C, graphite C10H22 CaO gold
Damm [24]

Answer:

C10H22

Explanation:

Molecular Solids comprises of a Vander waal's force of attraction between the molecule. These forces are very weak when compared to ionic and covalent bond.

In Carbon, Carbon is not a molecule but an atom. One of it unique characteristics is that it forms bonds with other carbon atoms. This property is know as catenation. The bond between these carbon atoms is know as covalent bond.

Graphite is an allotrope of carbon. It exists as black , slippery, hexagonal crystals.The carbon atoms in graphite forms flat layers and are joined together by strong covalent bonds. Graphite can be used as lubricant in engines.

Gold (Au) is an element on the periodic table with atomic number 79 and a mass number 197. It exists as a metal. Most times Gold forms hydrogen bonds.

C10H22 is known as decane. It is the tenth compound formed in the series of alkane family( an organic unsaturated carbon chain family). Alkanes are aliphatic hydrocarbons. The forces of attraction between the alkane family are weak.In decane , their exists Vander waal's force which makes Decane C10H22 a Molecular Solid.

6 0
4 years ago
A chemist prepares a solution of calcium bromide CaBr2 by measuring out 4.81μmol of calcium bromide into a 50.mL volumetric flas
Mariana [72]

Answer:

The concentration of the CaBr2 solution is 96 µmol/L

Explanation:

<u>Step 1:</u> Data given

Moles of Calciumbromide (CaBr2) = 4.81 µmol

Volume of the flask = 50.0 mL = 0.05 L

<u>Step 2:</u> Calculate the concentration of Calciumbromide

Concentration CaBr2 = moles CaBr2 / volume

Concentration CaBr2 = 4.81 µmol / 0.05 L

Concentration CaBr2 = 96.2 µmol /L = 96.2 µM

The concentration of the CaBr2 solution is 96 µmol/L

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