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nikdorinn [45]
3 years ago
8

Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g

as (O2) according to the following equation.. . 2H2O= 2H2 + O2 . . The molar mass of H2O is 18.01 g/mol. The molar mass of O2 is 32.00 g/mol. What mass of H2O, in grams, must react to produce 50.00 g of O2?. 14.07. 23.05. 28.14. 56.28
Chemistry
2 answers:
Setler [38]3 years ago
8 0
The balanced chemical reaction is:

<span>2H2O= 2H2 + O2
</span>
We are given the amount of oxygen to be produced in the reaction. The starting point for the calculations will be this amount.

50 g ( 1 mol O2 / 32 g O2 ) ( 2 mol H2O / 1 mol O2 ) ( 18.01 g H2O / 1 mol H2O) = 56.28 g of H2O is needed.

Therefore, the correct answer is the last option.
Katyanochek1 [597]3 years ago
3 0

Answer: In more simpler terms the answer is 56.28

Explanation:

The other dude explained it above ^^^

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The elements in the periodic table are arranged in order of increasing atomic number.

Explanation:

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A kinetics experiment is set up is set up to collect the gas that is generated when a sample of chalk consisting primarily of so
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Answer:

Correct option -D

Explanation:

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4 0
3 years ago
Using only the periodic table, write the symbol of the ion most typically formed by each of the
ahrayia [7]

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3 0
3 years ago
How many moles of oxygen are required to produce 4 moles of water?​
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Answer:

6 moles of oxygen

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5 0
3 years ago
Read 2 more answers
2.At 35°C, a small sample of methane gas (CH4) has a volume of 1.5 liters. The temperature of the methane gas is slowly cooled t
defon

Answer:

V₂ = 1.41 L

Explanation:

Given data:

Initial temperature = 35°C (35 +273.15 K = 308.15 K)

Initial volume = 1.5 L

Final temperature = 17°C (17+273.15 K = 290.15 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

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T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1.5 L × 290.15 K / 308.15 k

V₂ = 435.23 L.K / 308.15 k

V₂ = 1.41 L

5 0
3 years ago
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