Hey there :)
We can see that the solubility of salt increases with increasing temperature. This happens with most substances.
To find out the maximum mass of copper sulfate that can be dissolved in water at these temperatures, just interpret the graph.
Considering Y-axis as g copper sulfate/100 g water and the X-axis as the temperature in °C:-
<u>1)</u>
a: <u>0 °C - 14 g of copper sulfate/100 g of water</u>
b: <u>50 °C - 34 g of copper sulfate/100 g of water</u>
c: <u>90 °C - 66 g of copper sulfate/100 g of </u><u>water</u>
<u>2)</u> From the graph, we can infer that temperature affects the solubility of the salt.
<em>Answered</em><em> </em><em>by</em><em> </em><em>Benjemin360</em><em> </em>:)
Answer:
Back away from the situation and tell the supervisor/teacher
Answer:
The mass of copper(II) sulfide formed is:
= 81.24 g
Explanation:
The Balanced chemical equation for this reaction is :
given mass= 54 g
Molar mass of Cu = 63.55 g/mol
Moles of Cu = 0.8497 mol
Given mass = 42 g
Molar mass of S = 32.06 g/mol
Moles of S = 1.31 mol
Limiting Reagent :<em> The reagent which is present in less amount and consumed in a reactio</em>n
<u><em>First find the limiting reagent :</em></u>
1 mol of Cu require = 1 mol of S
0.8497 mol of Cu should require = 1 x 0.8497 mol
= 0.8497 mol of S
S present in the reaction Medium = 1.31 mol
S Required = 0.8497 mol
S is present in excess and <u>Cu is limiting reagent</u>
<u>All Cu is consumed in the reaction</u>
Amount Cu will decide the amount of CuS formed
1 mole of Cu gives = 1 mole of Copper sulfide
0.8497 mol of Cu = 1 x 0.8497 mole of Copper sulfide
= 0.8497
Molar mass of CuS = 95.611 g/mol
Mass of CuS = 0.8497 x 95.611
= 81.24 g
A. The fact that it's less dense than cold air.