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ExtremeBDS [4]
3 years ago
8

prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x^2 + y^2 = 5, i ha

ve 3/5 marks and i tried with perpendicular gradient.

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0

Answer:

I dont even know

Step-by-step explanation:

too complicated

Kamila [148]3 years ago
5 0

Answer:

You have to use the discriminant b^2 -4ac =0 because lines that cut a circle only once are tangents.

Step-by-step explanation:

I think you can use the perpendicular gradient, but it'll be more tedious because then you'll have to prove that the line touching the circle is perpendicular to the line from the centre to the circle to the point of intersection. You'll have to form an equation using the coordinates of the centre of the circle and the point of intersection. You probably had a careless mistake/ calculation error in this process.

Instead, try

1. equating the line to the circle (which you did), then

2. let the coefficient of x^2 be a, the coefficient of x be b, and the constant terms be c.

3. simplify b^2-4ac

3. prove that b^2-4ac=0 because there is only one real and distinct root, hence there is only one point of intersection.

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crimeas [40]

Answer:

  see below

Step-by-step explanation:

We assume you want the graph of ...

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A graphing calculator or spreadsheet is useful for this.

__

You know cos(θ) = cos(-θ), so the graph is symmetrical about the x-axis. You can evaluate the function at a few points to find the general outline.

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If f(x) = 2x2 + 3x and g(x) = x – 2, what is (f +
LUCKY_DIMON [66]
F(x) = 2x²+3x
g(x)= x-2

f(x)+ g(x) =( 2x²+3x ) +(x-2)
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= 14



hope to helped
4 0
3 years ago
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