Hmm, one way we can do this is by assigning numbers to each
A=4 and B=3
A>B because 4>3
so
A. 2(A+B)=2(4+3)=2(7)=14
B. A+B^2=4+3^2=4+9=13
C. A^2+B^2=4^2+3^2=16+9=25
D. A^2-B^2=4^2-3^2=16-9=7
the largest is 25 so C
Answer:
Acceleration=5m/s^2
Step-by-step explanation:
F=ma
1000=200xa
a=1000/200
a=5m/s^2
Answer:
15v^5+4v^3-24v^2
Step-by-step explanation:
Distribute the Negative Sign:
=3v5+8v3−10v2+−1(−12v5+4v3+14v2)
=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)
=3v5+8v3+−10v2+12v5+−4v3+−14v2
Combine Like Terms:
=3v5+8v3+−10v2+12v5+−4v3+−14v2
=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)
=15v5+4v3+−24v2
Answer:
=15v5+4v3−24v2
Hope this helps! :)
Answer:
d
Step-by-step explanation:
Answer:
0.025 grams
Step-by-step explanation:
The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:
Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)
Volume of drained water = 25 x 10⁻⁶ m³
Density of drained water = 1000 kg/m³
So, for the mass of drained water:
Density of drained water = Mass of drained water/Volume of drained water
Mass of drained water = (Density of drained water)(Volume of drained water)
Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)
<u>Mass of drained water = 0.025 gram</u>
Density