<u>Top row - Left Row :</u>
Order : Left to Right
{11.7 - below(negative)} , {11.6 - below(negative)} , {12 - exactly filled} , {12.2 - above(positive)}
<u>Middle Row </u>:
Order : Left to Right
{11.1 - below(negative)} , {11.2 - below(negative)} , {11.9 - below(negative)} , {12.5 - above(positive)}
<u>Right Row </u>:
Order : Left to Right
{12 - exactly filled} , {11.4 - below(negative)} , {11.5 - below(negative)} , {10.8 - below(negative)}
Answer:
(y+1)= -3(x-3)
Step-by-step explanation:
Use Point-Slope Formula
Substitute
Answer:
did u ever get hte answers for this ?
Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is
Where, 
is the point on the plane and 
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is
Therefore, the equation of the plane is .
108 = ( x)(48-x)
108 = 48x - x^2
48x -x^2 -108 = 0
I'm assuming you're doing solve the square right now, so you should be able to do the rest.
