Question

When does it reach maximum height? H(t)=-16t^2+112t+288

Answer 1

Answer:

484 feet  maximum

Step-by-step explanation:

H(t)=-16t^2+112t+288

The maximum height occurs at the vertex of this graph.  

Let us find the vertex.

vertex x-coordinate = -b/2a

x =  -b/2a = -(112)/ (2*-16) =  7/2 sec.

H(7/2) = - 16 *(7/2)^2 + 112*(7/2) +  288

H(7/2) = -196 + 392 + 288 = 484 feet ..