X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
Answer:
3x^2 + 9x + 1
Or
3x ( x + 3 ) + 1
Step-by-step explanation:
(5x - 2 +3x^2 ) + (4x + 3 )
To make this a little bit more easier to read, you can remove the parentheses:
5x - 2 + 3x^2 + 4x + 3
Now, write in a way so that the like terms are next to each other:
3x^2 + 5x + 4x - 2 + 3
Now simplify the 'x' terms to get:
3x^2 + 9x - 2 + 3
Now, simplify the integers (the ones with now variables with them) to get:
3x^2 + 9x + 1
If you want, you can factor out the 3x for two of the terms to get :
3x ( x + 3 ) + 1
Therefore, your simplest form can either be 3x^2 + 9x + 1 OR 3x (x + 3 ) + 1
<h2>
Answer: 1/5 or 0.2
_____________________________________</h2><h3>
Isolate the variable by dividing each side by factors that don't contain the variable.
Exact Form: x = 1/5
Decimal Form:
x = 0.2</h3><h3>
______________________________________________</h3>
Hope this helps!
Also can I please have Brainliest...?
<em>Only if I'm right of course...</em>
Answer:
Leslie determined that the system of equations below has infinitely many solutions. Is she correct?
x=4y-4
2x-8y=-24
A.Yes, Leslie is correct.
B. No, the solution is (-8,-24)
C. No, the solution is (0,-16)
<u>D. No, the system of equations has no solution. </u>
Step-by-step explanation:
you have to solve they as a pair of simultaneous equations and their is no solutions
if you need a more detailed explanation post the question again and i will write a detailed explanation
plz mark as brainliest
