AB=48, DC=88
48+88=136
136÷2=68
Answer: LM=68
Remember that the length of the mid segment in a trapezoid is half the sum of the base lengths.
Answer:
z = 10
Step-by-step explanation:
the steps have been attached above
Answer:
![cos \theta = -\frac{8}{17}](https://tex.z-dn.net/?f=%20cos%20%5Ctheta%20%3D%20-%5Cfrac%7B8%7D%7B17%7D)
Step-by-step explanation:
For this case we know that:
![sin \theta = \frac{15}{17}](https://tex.z-dn.net/?f=%20sin%20%5Ctheta%20%3D%20%5Cfrac%7B15%7D%7B17%7D)
And we want to find the value for
, so then we can use the following basic identity:
![cos^2 \theta + sin^2 \theta =1](https://tex.z-dn.net/?f=%20cos%5E2%20%5Ctheta%20%2B%20sin%5E2%20%5Ctheta%20%3D1%20)
And if we solve for
we got:
![cos^2 \theta = 1- sin^2 \theta](https://tex.z-dn.net/?f=%20cos%5E2%20%5Ctheta%20%3D%201-%20sin%5E2%20%5Ctheta)
![cos \theta =\pm \sqrt{1-sin^2 \theta}](https://tex.z-dn.net/?f=%20cos%20%5Ctheta%20%3D%5Cpm%20%5Csqrt%7B1-sin%5E2%20%5Ctheta%7D)
And if we replace the value given we got:
![cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}](https://tex.z-dn.net/?f=%20cos%20%5Ctheta%20%3D%5Cpm%20%5Csqrt%7B1-%20%28%5Cfrac%7B15%7D%7B17%7D%29%5E2%7D%3D%5Csqrt%7B%5Cfrac%7B64%7D%7B289%7D%7D%3D%5Cfrac%7B%5Csqrt%7B64%7D%7D%7B%5Csqrt%7B289%7D%7D%3D%5Cfrac%7B8%7D%7B17%7D)
For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:
![cos \theta = -\frac{8}{17}](https://tex.z-dn.net/?f=%20cos%20%5Ctheta%20%3D%20-%5Cfrac%7B8%7D%7B17%7D)
I think the incorrect data is the second x to the left.
Answer:
A
Step-by-step explanation:
A: 3 times a week, 45 minutes, 15 minutes, 4 weeks
In the beginning of the word problem it says Brian goes to the gym 3 times a week. We need to know that because you have to use that number later for multiplication.
The 45 minutes are important because he spends 45 minutes at the gym each visit.
The 15 minutes are important because you have to subtract that from 45 because 15 of the 45 minutes are spent on weights, the rest of the time is spent on the treadmill, and we need to know how long Brian is on the treadmill in 4 weeks.
So the equation should be: [(45-15)* 3]*4
Solution step-by-step:
45-15= 30 minutes for treadmill
30*3=90 minutes per week
90*4= 360 minutes in 4 weeks
Convert into hours:
360 minutes/60 minutes= 6 hours
Hope this helps!!! :D