Answer:
c
Step-by-step explanation:
because if you solve the problem it is equal to c
Answer:
970,200
Step-by-step explanation:
In a 100 man race, how many runners have the chance to finish first?
Answer 100.
Now that 1 person is first, how many runners could be second? Well, there are still 99 runners left, and any one of them could be second.
Answer 99.
How many can be third? Using the same idea as above, once one person is first and another is second, that leaves 98 people still running and trying for third. So how many can be in third?
Answer 98.
Now you need to do the math.
100 × 99 × 98 = 970,200
So there are 970,200 different ways.
Hope this helps!! Brainliest :) ?
<h3>Answer:</h3>
2/15
<h3>Explanation:</h3>
There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.
Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.
_____
<em>Comment on nCk</em>
The number of ways to choose k objects from n, when order does not matter, is ...
... n!/(k!(n -k)!)
For the computations above, we have ...
... 8C2 = 8·7/(2·1) = 28
... 21C2 = 21·20/(2·1) = 210
