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3 years ago

The center of a circle represented by the equation (x + 9)2 + (y − 6)2 = 102 is

Mathematics

2 answers:

KIM [24]3 years ago

8 0

X+y=48 you Can do afiyet this

german3 years ago

7 0

Anyways the center will be (-9;6)

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3 - 6k + 9g - 11 + 7g (Distribute it with like terms and stuff)

AURORKA [14]

Answer:

-6k+16g-8

Step-by-step explanation:

simplify

6 0

2 years ago

Higher Order Thinking What is the least multiple 6 and 8 have in common? Explain.

Dahasolnce [82]

Answer: 24

Step-by-step explanation:

6, 12, 18, 24

8, 16, 24

3 0

3 years ago

Read 2 more answers

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

GarryVolchara [31]

Question 6

1) $\overline{AB} \cong \overline{BD}$ , $\overline{CD} \perp \overline{BD}$ , O is the midpoint of $\overline{BD}$ , $\overline{AB} \cong \overline{CD}$ (given)

2) $\angle ABO, \angle ODC$ are right angles (perpendicular lines form right angles)

3) $\triangle ABO, \triangle CDO$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{BO} \cong \overline{OD}$ (a midpoint splits a segment into two congruent parts)

5) $\triangle ABO \cong \triangle CDO$ (LL)

Question 7

1) $\angle ADC, \angle BDC$ are right angles), $\overline{AD} \cong \overline{BD}$

2) $\overline{CD} \cong \overline{CD}$ (reflexive property)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\triangle ADC \cong \triangle BDC$ (LL)

5) $\overline{AC} \cong \overline{BC}$ (CPCTC)

Question 8

1) $\overline{CD} \perp \overline{AB}$ , point D bisects $\overline{AB}$ (given)

2) $\angle CDA, \angle CDB$ are right angles (perpendicular lines form right angles)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{AD} \cong \overline{DB}$ (definition of a bisector)

5) $\overline{CD} \cong \overline{CD}$ (reflexive property)

6) $\triangle ADC \cong \triangle BDC$ (LL)

7) $\angle ACD \cong \angle BCD$ (CPCTC)

8 0

2 years ago

Find the equivalent fraction of 2/3 having denominator 6 and 6 and numerator 10.

4vir4ik [10]

Step-by-step explanation:

having denominator 6,

X/6= 2/3

X= 4

so, 4/6= 2/3

having numerator 10,

10/X= 2/3

X= 15

so, 10/15= 2/3

7 0

3 years ago

Which of the following graphs shows the solution set for the inequality below? |x + 3|+ 7 > 8

uranmaximum [27]

Answer:

Step-by-step explanation:

|x+3|+7>8

|x+3|>8-7

|x+3|>1

either x+3>1

x>2

or x+3<-1

x<-4

7 0

3 years ago