X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
D a quadrilateral with one pair of parallel sides
<h3>
Answer: Choice D. 
</h3>
This is because we want to avoid having negative numbers under the square root. So we make the radicand to be 0 or larger.
The +1 at the end doesn't affect the domain.
<span> 1.08×10^15
------------------ = 0.4 x 10^4 = 4000
</span><span> 2.7×10^11
answer
4000 times greater</span>