Mg (s) + 2 HCl (aq) -> MgCl2 (aq) + H2 (g)
1) Number of mols of HCl, n
n = 6.3 L * 4.5 mol/L = 28.35 mol
2) ratio: 2 mol HCl / 1 mol Mg = 28.35 mol HCl / x mol Mg
x = 28.35 mol HCL * 1 mol Mg / 2 mol HCL = 14.175 mol Mg
3) Convert mol to mass using atomic mass of Mg
14.175 mol Mg * 24.3 g Mg / mol Mg = 344. 45 g
Answer: 344.45 g
Answer:
Mass = 0.158 g
Explanation:
Formula used,
P V = n R T
Or,
n = P V / R T
Putting values,
n = 0.948 atm . 0.025 L / 0.0821 L.atm.K⁻¹.mol⁻¹ . 291.45
n = 0.00099 mol
Note: we have changed pressure from mmHg to atm, volume from mL to L and temperature from C to K)
Also,
Mass = n . Molecular Mass
Mass = 0.00099 mol × 159.808 g/mol
Mass = 0.158 g
If it is assumed that there are only two isotopes then the percent abundance needs to add up to 100%
100-35= 65%
The second isotope will have a 65% abundance.
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Answer:
Explanation:
The pH of a solution can be found by using the formula
![pH = - log [ {H}^{+} ]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7BH%7D%5E%7B%2B%7D%20%5D)
Since we are finding the H+ ions we find the antilog of the pH
So we have
We have the final answer as
Hope this helps you
