2.45 °C
From the Ideal gas law (Combined gas law)
PV/T = P'V'/T' .....eq 1
Where:
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure
V' - final volume
T' - final temperature.
To proceed we have to make T the subject from eq.1
Which is, T = P'V'T/PV.......eq.2
We have been provided with;
Standard temperature and pressure (STP)
P = 760 mm Hg (SP - Standard Pressure)
T = 273.15 K (ST - Standard Temperature)
V = 62.65 L
P' = 612.0 mm Hg
V' = 78.31 L
T' = ? (what we require)
Therefore, we substitute the values into eq.2
T' =
.
T' = 275.60 K
T = (275.60 - 273.15) ......To °C
T = 2.45 °C
>>>>> Answer
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Answer:
A) The reaction is exothermic reaction
B) 46 gm CH3CH2OH = 1236KJ
15.3 gm ch3ch2OH = 1236/46 x 15.3
= 411.10 KJ..........released
therefore 1 KJ = 0.239 K cal
so, 411.10 x 0.239 kcal
= 98.2529 .................. released
c) 54 gm of H2O produced = 1236KJ
so, 42.7 gm H2O produced = 1236/54 x 42.7KJ
= 977.35 KJ released.
Explanation:
There are 337.23 × 10²³ atoms in 4 moles of aluminum sulfite Al₂(SO₃)₃.
Explanation:
The questions ask how many atoms are in 4 moles of aluminum sulfite Al₂(SO₃)₃?
To answer this we use the Avogadro's number to devise the following reasoning:
if in 1 mole of Al₂(SO₃)₃ there are 14 × 6.022 × 10²³ atoms
then in 4 moles of Al₂(SO₃)₃ there are X atoms
X = (4 × 14 × 6.022 × 10²³) / 1 = 337.23 × 10²³ atoms
Learn more about:
Avogadro's number
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