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Strike441 [17]
3 years ago
9

Are bonds broken or formed, throughout each phase change present on a heating curve?

Chemistry
1 answer:
lawyer [7]3 years ago
5 0
Yes

step by step explanation
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How many molecules in 3.4 moles of NH4NO3?
aliya0001 [1]

There are  20.5 x 10^24 molecules are present in 3.4 moles of NH4NO3.

<h3>How many molecules in 3.4 moles of NH4NO3?</h3>

We know that one mole of a substance has  6.022 × 10²³ molecules so in 3.4 moles of NH4NO3, we have 20.5 x 10^24 molecules if we multiply the  6.022 × 10²³ with 3.4.

So we can conclude that there are  20.5 x 10^24 molecules are present in 3.4 moles of NH4NO3.

Learn more about mole here: brainly.com/question/15356425

#SPJ1

5 0
2 years ago
What is the name of this compound?
Digiron [165]
2,2-dichloroheptane  because we have two Cl we should use the prefix ''di'' and the numbers "2" and "2" indicated that the two functional groups are located on the same second carbon 
6 0
3 years ago
Consider the formation of ammonia in two experiments. (a) to a 1.00-l container at 727°c, 1.30 mol of n2 and 1.65 mol of h2 are
emmasim [6.3K]
When it comes to equilibrium reactions, it useful to do ICE analysis. ICE stands for Initial-Change-Equilibrium. You subtract the initial and change to determine the equilibrium amounts which is the basis for Kc. Kc is the equilibrium constant of concentration which is just the ratio of products to reactant. 

Let's do the ICE analysis

      2 NH₃ ⇄ N₂ + 3 H₂
I         0        1.3    1.65
C     +2x       -x      -3x
-------------------------------------
E       0.1        ?        ?

The variable x is the amount of moles of the substances that reacted. You apply the stoichiometric coefficients by multiplying it by x. Now, we can solve x by:

Equilibrium NH₃ = 0.1 = 0 + 2x
x = 0.05 mol
Therefore,
Equilibrium H₂ = 1.65 - 3(0.05) = 1.5 mol
Equilibrium N₂ = 1..3 - 0.05 = 1.25 mol

For the second part, I am confused with the given reaction because the stoichiometric coefficients do not balance which violates the law of conservation of mass. But you should remember that the Kc values might differ because of the stoichiometric coefficient. For a reaction: aA + bB ⇄ cC, the Kc for this is

K_{C} = \frac{[ C^{c} ]}{[ A^{a} ][ B^{b} ]}

Hence, Kc could vary depending on the stoichiometric coefficients of the reaction.
8 0
3 years ago
A gas absorbs 10J of heat and is simulataneously comptessed by a constant external pressure of 0.5atm from 4L to2L in volume.Wha
Ne4ueva [31]

Answer:

B. 111 J

Explanation:

The change in internal energy is the sum of the heat absorbed and the work done on the system:

ΔU = Q + W

At constant pressure, work is:

W = P ΔV

Given:

P = 0.5 atm = 50662.5 Pa

ΔV = 4 L − 2L = 2 L = 0.002 m³

Plugging in:

W = (50662.5 Pa) (0.002 m³)

W = 101.325 J

Therefore:

ΔU = 10 J + 101.325 J

ΔU = 111.325 J

Rounded to three significant figures, the change in internal energy is 111 J.

7 0
3 years ago
A sample of hydrogen gas was collected over water. If the total pressure
Brut [27]
It would 47.7 because you would have to both minus the number together.
7 0
3 years ago
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