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3 years ago

Latita had 12 marbles. she gave 2 marbles to her friend she has 10/12 of her marbles left write answer in simplest form

Mathematics

1 answer:

zloy xaker [14]3 years ago

3 0

The answer would be 5/6.

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the mass of the sun is 2 x 10^30kg and the mass of earth is 6 * 10^24 kg. Approximately how many times greater is the mass of th

german

Answer:

The mass of sun is 333333.33 times greater than the mass of earth

Step-by-step explanation:

Given as :

The mass of the sun = $2\times 10^{30}$ kg

The mass of earth = $6\times 10^{24}$ kg.

Let The mass of sun is x times greater than the mass of earth

i.e The mass of sun = x × The mass of earth

or, $2\times 10^{30}$ kg = $6\times 10^{24}$ kg × The mass of earth

Or, x = $\dfrac{2\times 10^{30}}{6\times 10^{24}}$

Or, x = $\dfrac{2\times 10^{6}}{6}$

∴ x = 333333.33

So, The mass of sun = 333333.33 × The mass of earth

Hence, The mass of sun is 333333.33 times greater than the mass of earth Answer

6 0

2 years ago

HELP PLEASEEEE!!

Viefleur [7K]

Answer:

Step-by-step explanation:

6 0

3 years ago

12/16 - 7/18 in simplest form

Ivan

Answer:

The answer is $\frac{13}{36}$

Step-by-step explanation:

The formula is:

$\frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd}$

In this case :

$\frac{12}{16} - \frac{7}{18} = \frac{12 x 18 - 16x17}{16x18} = \frac{216 -112 }{288} = \frac{104}{288}$

To get the simples form notice both 104 and 288 are divisible by 8 and 104/8 = 13 and 288/8 = 36.

Thus $\frac{104}{288} = \frac{13}{36}$

6 0

2 years ago

If f(x)=4/x+2 and g is the inverse of f, then g'(10)=

evablogger [386]

Answer:

The value of g'(10)= $\frac{(-1)}{16}$

Step-by-step explanation:

Given function is f(x)= $\frac{4}{x} + 2$

Take f(x)=y

y= $\frac{4}{x} + 2$

Subtract 2 from both side.

y-2= $\frac{4}{x}$

x= $\frac{4}{y-2}$

The inverse of f(x) is written as $\frac{4}{y-2}$

It is said as g is inverse of f

g(y)=\frac{4}{y-2}[/tex]

g(y)= $\frac{4}{y-2}$

g(10)= $\frac{4}{10-2}$

g(10)= $\frac{1}{2}$

Differentiating both sides we get,

g'(y)= $\frac{4(-1)}{(y-2)^{2}}+0$

g'(y)= $\frac{(-4)}{(y-2)^{2}}$

To find g'(10)= $\frac{(-4)}{(10-2)^{2}}$

g'(10)= $\frac{(-1)}{16}$

5 0

2 years ago

10/10 in the simpliest form

inessss [21]

I think the answer to the question is 1

3 0

3 years ago

Read 2 more answers