Answer:
The value to the given expression is 8
Therefore ![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D8)
Step-by-step explanation:
Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed
Given expression can be written as below
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3)
To find the value of the given expression:
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D%5Cfrac%7B%28%2810%5E4%29%285%5E2%29%29%5E3%7D%7B%28%2810%5E3%29%285%5E3%29%29%5E3%7D)
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Therefore
Therefore the value to the given expression is 8
Answer:
your answer would be 21
~hope this is the right answer, have a great day/night~
Step-by-step explanation:
Let Marc's age be x. If Jeanine is twice as old as Marc, then her age will be 2x. If their ages added together are 24, then you can create the following equation:
2x + x = 24
3x = 24
x = 8
Remember that x is Marc's age. So if Marc is 8, and Jeanine is twice as old, she will be 16.
Answer:
I think it would be 34 because I divided 68.2 by 4 and got 17.05, so I multiplied that by 2, and it's closest to 34.
<em>So I think it's A.</em>
But y'all don't be mad if I'm wrong cuz I said I think.
