Answer:
probability=events over the sample space
A=1 b=8 c=8
h = [-8 +-sq root(64 - 4*1*8)] / 2
h = [-8 +-sq root(32)] / 2
h1 = -4 +
<span>
<span>
<span>
2.8284271247
</span>
</span>
</span>
h1 =
<span>
<span>
<span>
-1.1715728753
</span>
</span>
</span>
h2 = -4 -
<span>
<span>
2.8284271247
</span></span>h2 = -<span> 6.8284271247
</span>
The answer to your question is 30+4.+10+4
From the information: v is 64 while c is 5
Differentiate the new equation h=-16
+ 64t + 5 to get 
= -32t + 64.
no 13). At maximum height this derivative equals zero so: -32t + 64 = 0; -32t = -64; t=2.Hence ans is 2 secs
no 14). put t as 2 sec in the equation: h=-16 + 64t + 5. This gives
h=-16( 
) + 64(2) + 5; h=-64+128+5=69. Hence h is 69ft
