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Sladkaya [172]
3 years ago
7

Andre cycled a distance 25km in 150 minutes. What was his average speed (km/h)?

Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

10 km/h

Step-by-step explanation:

First, convert 150 minutes to hours:

150/60

= 2.5 hours

Then, to find his speed, divide the km by the number of hours:

25/2.5

= 10 km/h

CaHeK987 [17]3 years ago
3 0

Answer:

10 km / hr

Step-by-step explanation:

We want to find the average speed in kilometers per hour.

We know that Andre cycled 25 kilometers in 150 minutes.

First, we have the convert 150 minutes to hours.

There are 60 minutes in 1 hour, so we can divide 150 by 60.

150/60= 2.5

Next, find the average speed in kilometers per hour.

Divide the kilometers traveled by the hours.

speed = kilometers / hours

Andre cycled 25 kilometers in 2.5 hours.

speed= 25 km /2.5 hrs

speed = 10 km/hr

Andre’s average speed was 10 kilometers per hour.

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Amanda just took out a loan for $950 at a 7.2% APR, compounded monthly, to
vaieri [72.5K]

Answer:

C. 16 months faster

Step-by-step explanation:

You can solve this using a Financial calculator( TI BA II plus in this case)

First, find number of months if recurring monthly payment is $38.50;

Amount borrowed ; PV = -950

Monthly rate ; I/Y  = 7.2%/12 = 0.6%

Monthly payment; PMT = 38.50

Future value ; FV = 0

Total duration;  press CPT, N = 26.785  OR 27 months

Next, find number of months if recurring monthly payment is $93;

Amount borrowed ; PV = -950

Monthly rate ; I/Y  = 7.2%/12 = 0.6%

Monthly payment; PMT = 93

Future value ; FV = 0

Total duration;  press CPT, N = 10.573 OR 11 months

Difference = 27 -11 = 16

Therefore, she would be able to pay off the loan 16 months faster.

8 0
3 years ago
AB←→||CD←→. Find the measure of ∠BFG.
Colt1911 [192]

Answer:

Value of ∠ BFG = 135°

Step-by-step explanation:

Given:

AB || CD

∠ AFG = (3x + 15)°

∠ FGD = (5x - 5)°

Find:

∠ BFG

Computation:

We know that;

∠ AFG = ∠ FGD

3x + 15 = 5x - 5

3x - 5x = - 5 - 15

- 2x = - 20

2x = 20

x = 10

Value of ∠ AFG = 3x + 15

Value of ∠ AFG = 3(10) + 15

Value of ∠ AFG = 45°

∠ BFG = 180° - Value of ∠ AFG

∠ BFG = 180° - 45°

∠ BFG = 135°

Value of ∠ BFG = 135°

8 0
3 years ago
Quadratic function of Y=x2-2x-3
Svetach [21]
Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.

Hope this helps.</span>
6 0
3 years ago
Please help find domain and range
Oxana [17]
<h3>Answer:  Choice A</h3>
  • Domain:  x > 4
  • Range: y > 0

========================================================

Explanation:

We want to avoid having a negative number under the square root. Solving x-4 \ge 0 leads to x \ge 4

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

-------------

The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression \frac{3}{\sqrt{x-4}} is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

-------------

The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).

3 0
3 years ago
Read 2 more answers
Geometry question-- am I correct?
Fudgin [204]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
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