To find the intercept put a 0 where the y is in the equation <span>L = ax + by + c = 0. Also note, the a and b and c are there to represent real numbers.
</span><span> ax + b0 + c = 0 </span><span> ax + c = 0 </span><span> ax + c - c = -c </span><span> ax = -c </span> ax/a = -c/a <span>x = -c/a x-intercept = -c/a
To find the y-intercept put 0 were the x is located in the equation </span><span>ax + by + c = 0 and do the same thing as above. </span> <span>a0 + by + c =0 </span>by + c = 0 by +c -c = 0-c by = 0 -c by/b = -c/b y = -c/b The y-intercept is at -c/b
Why does putting a 0 where the x or y is located work? Well, the x-intercept point is (x,0). In this point, you will notice the 0 is located in the y position in(x,y).So to find the x-intercept we put the 0 in the y where it is located in <span>ax + by + c and then solve for x. This is also true for the y-intercept, which is at (0,y). The intercepts are on the axes. The y-intercetp is on the y axes at (0,y) and the x-intercept is on the x axes at (x,0)</span>
Ken has less than Joe. Joe has 10 marbles, so Ken (m) has less than 10. To transform the sentence, "Ken has less than 10," into an expression we use the < sign to show that Ken (m) has less than 10. M < 10
