- Solve 2m + n = 2 and 3m - 2n = 3 using substitution.
We can use the substitution method to solve linear equations of this form. Let's solve for m & n.
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.
Subtract n from both sides of the equation.
Divide both sides by 2.
Multiply 1/2 times -n+2.
Substitute 
for m in the other equation, 3m-2n=3.
Multiply 3 times .
Add 
to -2n.
Subtract 3 from both sides of the equation.
Divide both sides of the equation by 
, which is the same as multiplying both sides by the reciprocal of the fraction.
Substitute 0 for n in 
. Because the resulting equation contains only one variable, you can solve for m directly.
The system is now solved.
Figure 3
Step-by-step explanation:
Answer:
a) CI = ( 5,1 ; 5,7 )
b) SE = 0,1
Step-by-step explanation:
a) Sample random n = 100
Mean = μ = 5,4
Standard deviation s = 1,3
CI = 99 % α = 1 % α = 0,01 α/2 = 0,005
z(c) for 0,005 is from z-table z(c) = 2,575
z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n
CI = 5,4 ± 2,575* 1,3/10
CI = 5,4 ± 0,334
CI = ( 5,1 ; 5,7 )
b) SE = Standard deviation / √n
SE = 1,3 /10 SE = 0,1
We can support that with 99 % of probability our random variable will be in the CI.
Answer:
D. 140
Step-by-step explanation:
volume equals length times width times height 7 times 4 times 5 equals 140 good luck
