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Ivenika [448]
4 years ago
9

Write the slope-intercept form of the equation of the line that is parallel to and passes through Point X. Show all work for ful

l credit.

Mathematics
1 answer:
Lapatulllka [165]4 years ago
6 0

Answer:

y=-1/3x+12

Step-by-step explanation:

To write a parallel first find the slope-intercept form of the first line- y=-1/3x+4

Then rewrite the equation with a y-intercept that will create a second line that passes through X on the graph.

(Although I believe this is right, please correct me if it is not. I, of course, could have made a mistake.)

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The distance between points (X7, Yı) and (4, 8) is the square root of (x7 - 8)2 +
serious [3.7K]

Answer:

B. False

Step-by-step explanation:

Given

Points: (x_7 - y_i),(4,8)

Required

Is the distance between them \sqrt{(x_7 - 8)^2 + (y_1 - 4)^2}

Given that there are two points, the distance between them is calculated using

Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

In this case;

(x_1,y_1)= (x_7 - y_i)\\(x_2,y_2) =(4,8)

Substitute these in the given formula

Distance = \sqrt{(4- x_7)^2 + (8 - y_1)^2}

Comparing this with the given formula, both are not the same;

Hence, the formula is false and the correct formula is of the form \sqrt{(4- x_7)^2 + (8 - y_1)^2}

6 0
3 years ago
!MAGOR HELP!<br> Question and answers are in the pic
Simora [160]
The first one is correct (-2/3, -1/2, 7/12, 0.82) pls mark branliest
8 0
3 years ago
Read 2 more answers
I need help with percentages
satela [25.4K]

Answer:

3a. 7.2

3b. 0.9

4a. 7.2

4b. 2.4

5a. 104

5b. 260

hope this helps, everything in bold is the correct answer,

have an awesome day, -TJ

6 0
2 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
The table below shows pairs of value that satisfy a linear function.
neonofarm [45]

Answer:

-27

Step-by-step explanation:

4 0
3 years ago
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