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hram777 [196]
3 years ago
11

What do you notice about subtracting 0 from an integer? Why does this make sense?

Mathematics
1 answer:
madam [21]3 years ago
3 0
When you subtract an integer from 0 it is a negative number
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What are the solutions to the quadratic equation below?
Luden [163]

Using factorization method;

x²+13x+40=0

x²+13+40

Find two numbers that you can add together to give the co-efficient of variable x. (I.e 13 for this question). Also, you'll find two numbers that you can multiply with each other to give you the whole number as an answer. (I.e 40 in this question). The two numbers must be the same (i.e the two numbers that will be added to give the co-efficient of x and the two numbers that will be multiplied to give the whole number must be the same two).

The two numbers are +5 and +8

The equation will therefore be = x²+5x+8x+40

You'll then factorize (I.e use a common factor of both values to bracket them)

x(x+5)+8(x+5)

(x+8)(x+5)

x is therefore (x+8=0) or (x+5=0)

x=(x=0-8) or (x=0-5)

x= -8 or x= -5

5 0
2 years ago
What is the answer to 56 is 28% of
Alecsey [184]
To find this answer divide by the % and times by 100 
so 56/28 x 100 =200
so the answer is 200
3 0
3 years ago
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A total of 180 customers visited the store at the grand opening. Every 10th customer received a free sticker. Every 25th custome
adell [148]

Step-by-step explanation:

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4 0
3 years ago
Solve using the quadratic formula x2 - 6x - 40=0 Question options: x = 10 or x = -4 x = 4 or x = -10 x = -7 or x = 7 x = -4 - √7
Crazy boy [7]

Answer:

x=-10 or x=4

Step-by-step explanation:

ax^2+bx+c=0

x^2-6x-40=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-6\pm\sqrt{6^2-4(1)(-40)}}{2(1)}

x=\frac{-6\pm\sqrt{36+160}}{2}

x=\frac{-6\pm\sqrt{196}}{2}

x=\frac{-6\pm14}{2}

x=-3\pm7

x=-10 or x=4

6 0
3 years ago
Read 2 more answers
Find the value of f(-3).​
serious [3.7K]

Step-by-step explanation:

f  (-3)

f= x value

answer= y value

The answer is actually -3 because the y value for x is -3

3 0
3 years ago
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