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shepuryov [24]
3 years ago
9

To add a value 1 to variable x, you write ________.

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0
1+x you can not add them because they are not like terms
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Find the Missing Angles. (1 2 3 and 4)​
kicyunya [14]

Answer:

1=51°

2=18°

3=123°

4=39°

Step-by-step explanation:

3 0
2 years ago
What is the y intercept of y=7-2x
neonofarm [45]

Answer: It would be 7. (0,7)

4 0
3 years ago
You deposit $800 in an account that pays 2.25% annual interest compounded continuously. About how long will it take for the bala
timurjin [86]

Answer:

48.8 years

Step-by-step explanation:

A=p(1+r/n)^nt

A= total amount

p= initial investment (800_

r/n= annual interest rate over number of years( 2.25)

t= number of years compounded ( annually , biannually, quarterly etc.)

48.8 years

7 0
3 years ago
Jason can read 850 words in 5 minutes. Ashley can read 804 words in 4 minutes. Who reads at a faster pace per minut
Vedmedyk [2.9K]
850/5=170
804/4=201

Ashley can read faster
8 0
3 years ago
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
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