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3 years ago

To add a value 1 to variable x, you write ________.

Mathematics

1 answer:

Vaselesa [24]3 years ago

7 0

1+x you can not add them because they are not like terms

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Marking brainliest for a simple math problem

nalin [4]

Answer:

B. 88

Step-by-step explanation:

the total data = 1+2+4+5 = 12

the median is (a6+a7) /2

a6 = 87, a7 = 89

so, the median = (87+89)/2 = 88

7 0

3 years ago

Determine the most precise name for quadrilateral ABCD. Answers: parallelogram quadrilateral rhombus kite angles: (7,6) (3,5) (2

devlian [24]

Answer:

rhombus

Step-by-step explanation:

It is helpful to plot the points on a graph. There, you can see that the rise and run of each segment are 1 and 4 (or vice versa). This tells you they are the same length, but not perpendicular.

A quadrilateral with all sides the same length, but not perpendicular, is a rhombus.

3 0

3 years ago

In a sample of people on the school board 2 out of 5 were in favor of a new high school being built if 3,500 people vote in the

ioda

Answer:

Just about 2100 people

Step-by-step explanation:

2 out of 5 is 60% and 7*5 is 35 so if you multiply 7 by 3 then you get 21 and if you multiply that by 100 then you get 2100

7 0

3 years ago

Read 2 more answers

Your brother is 1/5 your age. Your sister is 9 years older than your brother. Your sister is 11 years old. Write and solve an eq

Papessa [141]

Brother=b
b+9=11
b=2
2=1/5a
10=a
a=10

The answer is 10

Hope this helps :)

5 0

3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

4 0

3 years ago