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Amiraneli [1.4K]
3 years ago
13

How many centimeters long is a 21 board

Mathematics
2 answers:
neonofarm [45]3 years ago
4 0
53.34 is the answer
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scoundrel [369]3 years ago
3 0
21, it says it right in the name.
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Business people have determined that three fourths of the items on a mailing list will change in one year. A business has a mail
Aliun [14]
1695 will be incorrect.
4 0
3 years ago
-8x^2+4x+5=0 using quadratic formula
daser333 [38]
So you want to solve for x?

It would be nice if this would easily factor:
(-4x + 5)(2x +1)  = 0    This will not work!

So you need to use the quadratic formula:
a = -8, b = 4, c = 5

x = \frac{-b+/-  \sqrt{b^{2}-4ac} }{2a}

x = (-4 +/- \sqrt{16-4(-8)(5)})/2(-8)
   = (-4 +/- \sqrt{16 + 160})/-16
   = (-4 +\sqrt{176})/-16
   = 1/4 - \sqrt{11}/4

6 0
3 years ago
I want the answer to this problem<br> 3(x+2)-x=38
maks197457 [2]

Answer:

x = 16

Step-by-step explanation:

3(x+2)-x=38

Distribute

3x+6 -x = 38

Combine like terms

2x+6 = 38

Subtract 6 from each side

2x+6-6 = 38-6

2x = 32

Divide each side by 2

2x/2 = 32/2

x = 16

5 0
3 years ago
Read 2 more answers
For the point P (-17,25) and Q(-10,30), fins the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
Nonamiya [84]

Answer:

Distance = 8.6

M = (-13.5,27.5)

Step-by-step explanation:

Distance = \sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2

= \sqrt{(-10_ }- (-17)_{ })^2 + (30_{ }- 25_{ })^2

= \sqrt{(-10_{ }+ 17_{ })^2 + 5^2_

= \sqrt{7^2+5^2}

= \sqrt{49+25}

= \sqrt{74}

= 8.6

Midpoint = (\frac{x_{2}+x_{1}}{2};\frac{y_{2}+y_{1}}{2})

= (-10+(-17)) ÷ 2 ; (30+25) ÷ 2

= -27 ÷2 ; 55 ÷ 2

= -13.5, 27.5

3 0
3 years ago
3m-2x for m = 5 and x = 4
kipiarov [429]
M = 5 and x = 4

3(5) - 2(4)
15 - 8 = 7

I hope this helps!
3 0
3 years ago
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