When the top right-hand capacitor is filled with a material of dielectric constant κ, the charge on this capacitor is increases
by a factor of 1.35. Find the dielectric constant κ of the material inserted into the top right-hand capacitor.
2 answers:
Answer:
Explanation:
Given:
Capacitance, c1 = c2 = c3 = c4
= 80 micro farad
Voltage, v = Eb
= 4 V
We are not concerned with c3 and c4 just c1 and c2,
Since c1 and c2 are in series,
1/ct = 1/c1 + 1/c2
vab = v1 + v2
= q'/c1 + q'/c2
But c2 = κ × c,
= q'/c + q'/κc .....1
Let c1 = c2 = c,
Vab = q/c + q/c
= 2 × q/c. ........2
Equating equation 1 and 2,
q'/c + q'/κc = 2q/c
q'/c × (1 + 1/κ) = 2q/c
q'/q = 2κ/(1 + κ)
But q'/q = 1.35
2κ/(1 + κ) = 1.35
0.65κ = 1.35
κ = 1.35/0.65
= 2.077
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Answer:
The inlet velocity is 21.9 m/s.
The mass flow rate at reach exit is 1.7 kg/s.
Explanation:
Given that,
Mass flow rate = 2 kg/s
Diameter of inlet pipe = 5.2 cm
Fifteen percent of the flow leaves through location (2) and the remainder leaves at (3)
The mass flow rate is
We need to calculate the mass flow rate at reach exit
Using formula of mass
We need to calculate the inlet velocity
Using formula of velocity
Put the value into the formula
Hence, The inlet velocity is 21.9 m/s.
The mass flow rate at reach exit is 1.7 kg/s.