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katrin2010 [14]
3 years ago
12

35 pts please help quick

Physics
1 answer:
Studentka2010 [4]3 years ago
8 0

yes the car is chaning direction throught the track, so it is accelerting.


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Hydrated iron(III) oxide, or ferric oxide

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An ideal fluid flows through a pipe of variable cross section without any friction. The fluid completely fills the pipe. At any
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4. total energy

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for ideal fluid flows through a pipe of variable cross section without any friction. The fluid completely fills the pipe. At any given point in the pipe, the fluid has a constant Total Energy.

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Sound travels around 340 m/s the function d(t =340 gives the distance d(t in meters that sound travels in t seconds how far does
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2 years ago
A 84.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 36.0 m/s. If both are initially at rest and if t
AysviL [449]

Answer: 3333333222135790075

Explanation:Set term u equal to initial velocity for simplicity

Set V equal to final velocity for simplicity

2

To begin this problem, one must look at the system to have multiple stages. These being before and after hitting the puck. In these first few steps, we look at BEFORE the human hits the puck

3

This collision is elastic because the puck and the human do not join together after interaction

4

Because the initial velocity of both the puck and the human are both 0, the terms on the left of the equal sign become 0

5

Solving for the final velocity of the human gives this formula. This number should be negative as the negative indicates the direction he is going (left)

The final velocity of the puck is already given in the problem

6

Because the ice is frictionless, the final velocity before hitting the puck is equal to the initial velocity after hitting the puck

Now we begin to look at the system AFTER the puck has been hit

7

Using the formula for final position allows us to solve for time it takes the puck to travel the distance given

8

9

Solve for time

10

We can now use the formula for the final position of the human to solve for the final answer

11

12nuewnfunw

Plugging in formulas from steps 5 and 9 gives the final answer

<h2>Again, this number should be negative as the negative sign denotes the direction the human is going. Because the problem does not ask for snijndij   hinu9nub hvtj c  v7 yf jhmb tfgnb nb fyhgbv </h2>

4 0
2 years ago
Determine the instantaneous velocity of the car at t = 4.7 s, using time intervals of 0.40 s, 0.20 s, and 0.10 s. (In order to b
weeeeeb [17]

Answer:

4.408 m/s, 4.102 m/s, 4.026 m/s

Explanation:

The question is incomplete. The text of the original question states:

A race car moves such that its position fits the relationship

:

x=(4.0 m/s)t + (0.85 m/s^3) t^3

where x is measured in meters and t in seconds. Determine the instantaneous velocity of the car at t = 4.7 s, using time intervals of 0.40 s, 0.20 s, and 0.10 s.

We can find the instantanoues velocity of the car at any time t by calculating the derivative of the position, so we find:

v(t) = x'(t) = 4.0 m/s + 3\cdot (0.85 m/s^2) t^2 = 4.0 m/s + (2.55 m/s^2) t^2

And now we just need to substitute t=0.40 s, 0.20 s, and 0.10 s to find the corresponding instantaneous velocity:

v(0.40) = 4.0 + 2.55 (0.40)^2 = 4.408 m/s\\v(0.20) = 4.0 + 2.55 (0.20)^2 = 4.102 m/s\\v(0.10) = 4.0 + 2.55 (0.10)^2 = 4.026 m/s

5 0
3 years ago
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