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garik1379 [7]
3 years ago
7

Paulene is using this table in Word,and she started with the cursor in the box that read “Flavor”. she then hits Alt+End,The the

down arrow three times,then the left arrow once.What Does this cell read?
A.6
B.12
C.Strawberry
D.$60

Computers and Technology
1 answer:
vlada-n [284]3 years ago
3 0
Hi!
The shortcut Alt-End sends you to the last cell in a row, which in this case would be the cell that reads Revenue. Going down 3 cells would lead you to the cell that reads 60, and going left once will take you to the final cell- 6.
The answer is A: 6
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1 year ago
(1) Experiment Purpose
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1 year ago
Write a function: function solution(N); that, given a positive integer N, prints the consecutive numbers from 1 to N, each on a
koban [17]

Answer:

<em>The program written in Python is as follows:</em>

def solution(N):

     concat = ""

     for i in range(1,N+1):

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

           else:

                 if i%2 == 0:

                       concat= concat+"Codility"

                 if i%3 == 0:

                       concat= concat+"Testers"

                 if i%5 == 0:

                       concat= concat+"Coders"

                 print(concat)

                 concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

     concat = ""

This line iterates from 1 to the input integer

     for i in range(1,N+1):

<em>This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed</em>

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

<em>If otherwise</em>

           else:

<em>This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat</em>

                 if i%2 == 0:

                       concat= concat+"Codility"

<em>This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat</em>

<em>                 </em> if i%3 == 0:

                       concat= concat+"Testers"

<em>This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat</em>

                 if i%5 == 0:

                       concat= concat+"Coders"

<em>The concatenated string is printed using this line</em>

                 print(concat)

This variable concat is intialized back to an empty string

                 concat = ""

The main method starts here

N = int(input("Enter a positive integer: "))

This line calls the defined function solution

solution(N)

6 0
3 years ago
Technician A says that the excessive length of a heater hose is intended to protect the heater core from undue stress. Technicia
hammer [34]
It is both true that <span>Technician A says that the excessive length of a heater hose is intended to protect the heater core from undue stress. Technician B says that excessive wear adds to the length of a heater hose, and a replacement heater hose should be roughly three to four inches shorter than its predecessor.  So the asnwer is letter B.</span>
6 0
3 years ago
Write an if/else statement that compares the double variable pH with 7.0 and makes the following assignments to the int variable
levacccp [35]

Answer:

if (pH<7.0){

          neutral=0;

          base=0;

          acid=1;

      }

      else if (pH>7.0){

          neutral=0;

          base=1;

          acid=0;

      }

      else if (pH==7.0){

          neutral=1;

          base=0;

          acid=0;

      }

Explanation:

As required by the question, if and else statements have been used to test the value of the pH and assign the apropriate values to the variables neutral, base and acid.

The code snippet below can be used to prompt the user to enter values for pH

<em>import java.util.Scanner;</em>

<em>public class pHTest {</em>

<em>   public static void main(String[] args) {</em>

<em>      Scanner scr = new Scanner(System.in);</em>

<em>       System.out.println("Enter a value for the pH");</em>

<em>       int neutral, base, acid;</em>

<em>       double pH = scr.nextDouble();</em>

<em> if (pH<7.0){</em>

<em>           neutral=0;</em>

<em>           base=0;</em>

<em>           acid=1;</em>

<em>       }</em>

<em>       else if (pH>7.0){</em>

<em>           neutral=0;</em>

<em>           base=1;</em>

<em>           acid=0;</em>

<em>       }</em>

<em>       else if (pH==7.0){</em>

<em>           neutral=1;</em>

<em>           base=0;</em>

<em>           acid=0;</em>

<em>       }</em>

<em>} }</em>

4 0
3 years ago
Read 2 more answers
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