Please hurry: What is the approximate astronomical distance in AUs between the Sun and Mercury, the closest planet to the Sun?

Problem 7-35 A satellite range prediction error has the standard normal distribution with mean 0 NM and standard deviation 1 NM.

hammer [34]

Answer:

Kindly check explanation

Step-by-step explanation:

For a normal distribution with :

Mean(m) = 0

Standard deviation (s) = 1

Calculate :

(a) less than 1.17 NM Probability

Zscore = (x - m) / s = (1.17 - 0) / 1 = 1.17

P(z < 1.17) = 0.879

(b) between 1.04 NM and 1.99 NM Probability

Zscore = (x - m) / s = (1.04 - 0) / 1 = 1.04

P(z < 1.04) = 0.8508

Zscore = (x - m) / s = (1.99 - 0) / 1 = 1.99

P(z < 1.99) = 0.9767

(0.9767 - 0.8508) = 0.1259

(c) greater than 0.93 NM Probability

P(Z > 0.93) = 1 - p(Z < 0.93) = 1 - 0.8238 = 0.1762

(d) between 0.24 NM and 0.73 NM Probability

P(Z < 0.24) = 0.5948

P(Z <0.73) = 0.7673

0.7673 - 0.5948 = 0.1725

(e) less than or equal to 2.3 NM Probability

P(Z ≤ 2.3) = 0.9893

(f) greater than 2.22 NM or less than .65 NM

P(Z > 2.22) = 1 - p(Z < 2.22) = 1 - 0.9868 = 0.0132

P(Z < 0.65) = 0.7422

0.7422 - 0.0132 = 0.729

(g) greater than or equal to 2.0 NM Probability

P(Z ≥2) = 1 - p(Z ≤ 2)

1 - 0.97725 = 0.02275

3 0

3 years ago

Solve<br> 1.)solve 15 > - 2x -9<br> 2.) solve 3x + 8 < 29

kipiarov [429]

1)
15 > -2x-9
15+9 > -2x
24÷(-2) < x (the sign flips because you divide both sides by a negative number)
Hence, x > -12

2)
3x + 8 < 29
3x < 29-8
3x < 21
x < 7 (tada the answer)

5 0

3 years ago

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In the Numbers Game, a state lottery, four numbers are drawn with replacement from an urn containing balls numbered 0-9, inclusi

Fantom [35]

There are 10 digits from 0 to 9, inclusive.

Thus, number of ways in which four numbers will be drawn from an urn containing balls numbered 0-9, inclusive is given by $10^4=10,000$

The number of ways in which a ticket holder will have the first two digits in the correct order is the same as the number of ways in which two numbers will be drawn from the urn containing balls numbered 0-9, inclusive and is given by $10^2=100$

Therefore, <span>the probability that a ticket holder has the first two digits in exact order is given by $\frac{100}{10,000} = \frac{1}{100} =0.01$ </span>