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3 years ago

What's the value of a when 3-a+5-2a=17

Mathematics

2 answers:

Sveta_85 [38]3 years ago

8 0

First combine like terms to get:
-3a + 8 = 17

Solve by subtracting 8 then dividing by -3:
-3a = 9
a = -3

Flura [38]3 years ago

6 0

Here's are the steps to solving it.

3-a+5-2a=17
-3a=9
a=-3

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Simplify 7-5x-(3+5x)

galben [10]

Answer:

-10x +4

Step-by-step explanation:

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2 years ago

Evaluate 5j +12 foreach listed<br> value ofn.<br> j= 4<br> j = 6

Bezzdna [24]

Answer: 32 and 42

Step-by-step explanation:

5j +12

j= 4

j = 6

5(4) + 12

5 times 4 = 20

20 + 12 = 32

5(6) + 12

5 times 6 = 30

30 + 12 = 42

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2 years ago

Read 2 more answers

I purchase a new gaming system on opening night. Since I am one of the first 100 customers to purchase the system, the store giv

posledela

Answer:

2500

Step-by-step explanation:

50020%50020%

Convert 20%20% to a decimal.

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Divide 500500 by 0.20.2.

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7 0

2 years ago

Factor 54+2754+27 using the GCF.

torisob [31]

~54: 1,2,3,6,9,27~

~2,754:1,2,3,6,9,17,18,27,34,51,54,81,102,153,162,
306,459, 918,1377,2754~

~27: 1,3,9,27~

GCF: 27

Your answer would be for the GCF would be 27

6 0

3 years ago

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

3 years ago