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OlgaM077 [116]
4 years ago
8

What's the value of a when 3-a+5-2a=17

Mathematics
2 answers:
Sveta_85 [38]4 years ago
8 0
First combine like terms to get:
-3a + 8 = 17

Solve by subtracting 8 then dividing by -3:
-3a = 9
a = -3
Flura [38]4 years ago
6 0
Here's are the steps to solving it.

3-a+5-2a=17
-3a=9
a=-3
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Solve the Equation. 14x+28=14
Korvikt [17]

Answer:

x= -1

Step-by-step explanation:

1. First, you need to combine like terms. Constants with constants and variables with variables. Since there is only one variable, there is nothing to combine it with so nothing happens to it. The constants, on the other hand, can combine.

2. You have to subtract 28 from 28 and 14 so that +28 can cancel out on the left side and combine on the right.

3. That will leave you with 14x= -14.

4. Now you need to get x on its own so you need to divide 14 (opposite of multiplication to cancel out) on both sides.

5. That will leave you with x= -1. That is your final answer.

Hope this helps! Please vote me as Brainliest. Let me know if you need more of an explanation. Remember, cheating is never the answer. Try your best before you seek answers. Hope it's not too late. Good luck with whatever you are doing! Have an amazing day!

8 0
3 years ago
quinn is playing video games at a virtual reality game room . The game room charges 20 dollars for every 30 minutes of play time
USPshnik [31]

Answer:$100

Step-by-step explanation:

He need five periods of play time because 150 divided my 30 is 5. Then, you multiply 5 times the $20 because it is $20 for every 20 minutes.

Therefore, the answer is 20.

5 0
3 years ago
Does anyone have any questions that need help and will give brainlyest. i only need 3 brainlyest
vodomira [7]

Answer:

Step-by-step explanation:

mee

10)  Do the following graphs represent a linear or non-linear relationship?  How do you know this?

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3 years ago
Read 2 more answers
Find all the complex roots of the equation x4 − 16 = 0.
TiliK225 [7]

Answer:

4+16=0

4=−16=162

2=±4

Case 1  2=+4

=±2√

√=±(12√+12√)

=±2‾√+2‾√

Case 2  2=−4=43

=±23/2=±2()1/2

∵√=±(12√+12√)

=±(2‾√+2‾√)

So in all,

=2‾√+2‾√

=−2‾√+2‾√

=2‾√−2‾√

=−2‾√−2‾√

Let  √=+

Squaring both sides, we have

=(+)2

0+1=2−2+2⟹

2−2=0(1)

2=1

=12

Plugging in  (1)  … ⟹

2−1(2)2=0

4=14

2=12

∴=±12‾√

∴=±12‾√

∴√=+=±(12+12)

This can also be shown as below

√=12+12

Or

√=−12−12 \

3 0
3 years ago
20{5[100-2(25+25)+20)]
svetoff [14.1K]
20{5[100-2(50)+20]}
20{5[100-100+20]}
20{5[20]}
20(100)
20000
3 0
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