Answer:
filetype:xml AND site:example.Com
Explanation:
For this specific scenario, we will use three advanced google's search modifiers: filetype, site & AND
filetype:<em>[abc]</em>
Limit results to files matching the [<em>abc</em>] extension, like <em>pdf</em>, <em>txt</em>, <em>jpeg</em>. In this example xml.
site:<em>[domain]</em>
Limit results to websites containing the [<em>domain</em>] in the url, like .edu, <em>.gov</em>, <em>.brainly.com</em>. In this example example.com.
<em>[condition1] </em>AND <em>[conditon2]</em>
Limits results to those matching both conditions joined by the <em>AND. </em>In this example, the search results must match both filetype AND site domain.
Joining all conditions in a single query:
filetype:xml AND site:example.Com
Answer:
Turn of Data, your going to want to go onto a game app that takes a lot of Internet and see how fast that makes it run. That should really test it. I hope this helps!
Explanation:
Answer:
d. d1− = 10, d1+ = 0
Explanation:
Given
3X1 + 4X2 +d1− − d1+ = 36
X1 = 6
X2 = 2
Required
Possible values of d1- and d1+
We have:
3X1 + 4X2 +d1− − d1+ = 36
Substitute values for X1 and X2
3 *6 + 4 * 2 + d1- - d1+ = 36
18 + 8 + d1- - d1+ = 36
Collect like terms
d1- - d1+ = 36 - 18 - 8
d1- - d1+ = 10
For the above equation to be true, the following inequality must be true
d1- > d1+
Hence,
(d) is correct
Because:
10 > 0
The default constraint gives a value to an attribute when a new row is added to a table.
<h3>Is default a kind of constraint?</h3>
This is known to be a type of constraint that often apply a value to a column if an INSERT statement does not really give the value for the column.
Therefore, one can say that the default constraint gives a value to an attribute when a new row is added to a table.
Learn more about default constraint from
brainly.com/question/19130806
#SPJ12
Answer:
listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
listString = [ ]
for i in range(14):
if listNumbers[i]%2!=0 and listNumbers[i]%5==0:
listString.append("five odd")
elif listNumbers[i]%5==0 and listNumbers[i]%2==0:
listString.append("five even")
elif listNumbers[i]%2==0:
listString.append("even")
elif listNumbers[i]%2!=0:
listString.append("odd")
print(listNumbers)
print(listString)
Explanation:
In python programming language;
- Create two lists
- The first is a list of numbers and initialize it with random values: listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
- The second list is empty and will hold the string values listString = [ ]
- Use a for loop to iterate over all the elementts in the list of numbers
- Use the modulo operator (%) to chech for multiples of particular numbers as stipulated by the question
- Use combination of if/elif statements for each condition
- Use the .append method to add the elements into the list of strings
- finially output both lists
See attached code and output
