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2 years ago

Can you guys sxxxub to my channel XxDuckyxX it has 225 suxvxvxvbs and I do giveaways

Mathematics

1 answer:

natulia [17]2 years ago

8 0

Sure! quick question. What type of videos do you make? Like the genre.

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What is the slope of the line passed through the points ( 1, -5) and 4,1?

Allisa [31]

If you use the slope formula, the answer is m = 2

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3 years ago

How many times does 0.75 fit into 9 wholly I need help

nexus9112 [7]

Answer:

12. 9÷0.75.

Thank you. please mark me the braniliest.

3 0

1 year ago

What is the solution to the system of equations graphed below? y=-4x + 33 y=5/3x-1

Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. brainly.com/question/13675950

3 0

3 years ago

Read 2 more answers

PLEASE HELP IM GIVING BRAINLIEST one thing that's for sure its not C) 5 2/9

Tanzania [10]

Answer:

D) 5 4/9

Step-by-step explanation:

$\frac{19}{9}+(\frac{-2}{9})+\frac{32}{9}\\\frac{19-2}{9}+\frac{32}{9}\\\frac{17+32}{9}=\frac{49}{9}=5\frac{4}{9}$

4 0

2 years ago

Read 2 more answers

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

2 years ago