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____ [38]
3 years ago
8

Describe the advantages you see in using a rule for a function rather than listing function values in a table.​

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

Using a rule is direct and not time wasting, which is not the case for listing functions

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A self-serve car wash charges $5.87 to use its facilities, plus an additional $0.59 for each minute the customer is at the self-
Otrada [13]

$0.59 x 8 = 4.72

4.72 + 5.87 = 10.59

Hope this helped, please mark brainliest :)

7 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }

The critical value of <em>t</em> is:

\alpha /2=0.05/2=0.025

degrees of freedom =n_{1}+n_{2}-2=200+200-2=398

t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96

Compute the 95% confidence interval for the difference between two mean as follows:

CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0
3 years ago
Help asap pls!!!! correct answers only
zzz [600]

Answer:

6

Step-by-step explanation:

w/w+6 = 1/2

2w = w+6

w=6

3 0
3 years ago
Hii! I need some help, would anyone mind helping me?
Kisachek [45]

Step-by-step explanation:

{x}^{2}  - 14x  - 25 {y}^{2}  + 100y = 76

Factor by grouping,

( {x}^{2}  - 14x)   - (25 {y}^{2}  - 100y) = 76

Complete the square, with the x variables,

( {x}^{2}  - 14x + 49)  - (25 {y}^{2}  - 100y) = 125

Factor out 25 for the y variables

( {x}^{2}  - 14x + 49) - 25( {y}^{2}  - 4y) = 125

Complete the square

( {x}^{2}  - 14x + 49) - 25( {y}^{2}  - 4y + 4) = 25

Simplify the perfect square trinomial

(x - 7) {}^{2}  - 25(y - 2) {}^{2}  = 25

Make the right side be 1 so divide everything by 25.

\frac{(x - 7) {}^{2} }{25}  -  (y - 2) {}^{2}  = 1

Here our center is (7,2).

8 0
2 years ago
For what value of x is the function g(x)=x/1-x NOT defined?
VMariaS [17]

The function is definately defined at x=0 but not x=1.

But its just one part of the coordinate (x,y).

If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.

Now I hope you understood what I meant!

Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:

6 0
4 years ago
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