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____ [38]
3 years ago
8

Describe the advantages you see in using a rule for a function rather than listing function values in a table.​

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

Using a rule is direct and not time wasting, which is not the case for listing functions

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Calculate the mean 12,2,8,6,57
Rzqust [24]
12+2+8+6+57=85

85/5= 17

mean=17
6 0
3 years ago
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Susie’s Sweet Shop sells chocolate boxes that contain three types of chocolate truffles: solid chocolate truffles, cream center
olganol [36]

Let us make a list of all the details we have

We are given

The cost of each solid chocolate truffle = s

The cost of each cream centre chocolate truffle = c

The cos to each chocolate truffle with nuts = n

The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25

That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)

The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75

That is 10s+5c+10n = $68.75

The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00

That is 12s+12n=$66.00

Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.



6 0
3 years ago
Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your
lilavasa [31]

We have the equation:

y=a\cdot b^x

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}

Now, we use the point (2, 108/25) to calcualte b:

\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}

Then, we can write the equation as:

y=3\cdot(\frac{6}{5})^x

5 0
1 year ago
Each problem below gives the endpoints of a segment. Find the coordinates of the midpoints of each segment. A.(5, 2) and (11, 14
kvv77 [185]

The midpoints are (8,3) and (6.5,6).

<u>Step-by-step explanation</u>:

Midpoint formula = ((x1+x2)/2 , (y1+y2)/2)

(x1,y1) = (5,2)

(x2,y2) = (11,4)

Midpoint = ((5+11)/2 , (2+4)/2)

⇒ ((16/2) , (6/2))

⇒ (8,3)

(x1,y1) = (3,8)

(x2,y2) = (10,4)

Midpoint = ((3+10)/2 , (8+4)/2)

⇒ ((13/2) , (12/2))

⇒ (6.5,6)

8 0
3 years ago
A man walks 10 km, then travels a certain distance by train and then by bus as far as twice by the train. If the whole journey i
Nostrana [21]

Answer:

The man traveled 20km by train.

Step-by-step explanation:

If x is the distance he traveled by train, you can write this equation to represent the situation:

10+x+2x=70

Then, you can simply solve for x:

10+3x=70\\3x=60\\x=20

The man traveled 20km by train.

10+(20)+2(20)=70\\10+20+40=70\\70=70

3 0
2 years ago
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