The mean absolute deviation shows the average distance number data is from each other. The bigger it is the farther the numbers are away from each other and vice versa.

7 0

1 year ago

GIVE CORRECT ANS FOR BRAINLIEST

gizmo_the_mogwai [7]

<h3>Solution:</h3>

$2 \frac{5}{6} - 2 \frac{1}{2} \\ = \frac{17}{6} - \frac{5}{2} \\ = \frac{17 - 15}{6} \\ = \frac{2}{6} \\ = \frac{1}{2}$

<h3>Answer:</h3>

$\frac{1}{2}$

Hope it helps.

Do comment if you have any query.

7 0

2 years ago

Read 2 more answers

Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia

Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 75, \sigma = 12.5$