Question

The orbital period of a satellite is 2 x 106 s and its total radius is 2.5 x 1012 m.

Answer 1

Answer:

7,853,982   is the correct answer on Edge 2020

Explanation:

Answer 2

Explanation:

Orbital period = 2 x 10⁶s

Total radius = 2.5 x 10¹²m

Unknown:

Tangential speed of the satellite = ?

Solution:

The tangential speed simply expresses the rate at which the distance moves around its orbit with time.

   Since the orbit is taken to be circular;

Tangential speed = $\frac{2 x pi x r}{t}$

  r is the radius

  t is the time or orbital radius

  Tangential speed = $\frac{2 x 3.14 x 2.5 x 10¹²}{2 x10[tex]^{6}$}[/tex]

Tangential speed = 7.85 x 10⁶m/s

Learn more:

Circular motion brainly.com/question/2562955

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