One advantage is that whatever resource it is, it will never run out and you wont have to worry about not having it. A second is that there is going to be enough for everyone to use however much they want without there having to be a limit on how much you use.
Answer:
The density of plastic is equal to 0.6 g/mL.
Explanation:
Given that,
The mass of piece of plastic, m = 15 g
It is placed in a graduated cylinder. The water level in the graduated cylinder rises from 30 mL to 55 mL when the plastic is added.
We need to find the density of plastic.
Rise in volume = 55 mL - 30 mL
= 25 mL
The density of an object is given by :

So, the density of plastic is equal to 0.6 g/mL.
Answer:
Explanation:
The tip of the second hand moves on a circular path having radius equal to .22 m . Redial acceleration is given by the expression
ω²R where ω is angular velocity and R is radius of the circular path .
angular velocity of second hand = 2π / T where T is time period of circular motion . For second hand it is 60 s.
ω = 2π / T
= 2π / 60
= .1047
angular acceleration = .1047² x .22
= 2.41 x 10⁻³ rad / s² .
Answer: 11.2 AU
Explanation:
Applying Kepler's 3rd law, we can find out the average distance of planet B to the star.
This Law states that for planets orbiting a same star, there exists a fixed relationship between the average distance to the star, and the period of his orbit around it, as follows:
K = T² / d³
So , in this case, we can write:
(da)³ / Ta² = (db)³ / (Tb)²
Solving for db:
db = ∛8³.(1170)² / 710² = ∛1390.4 = 11.2 AU
Answer:
1) v = 0.45 m/s
2) v = 0.65 m/s
3) v = 0.75 m/s
Explanation:
1) We can find the speed of the object by conservation of energy:


Where:
k: is the spring constant = 280 N/m
v: is the speed of the object =?
m: is the mass of the object = 5.00 kg
x: is the displacement of the spring

2) When the object is 5.00 cm (0.050 m) from equilibrium, the speed of the object is:
3) When the object is at the equilibrium position, the speed of the object is:

I hope it helps you!