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mezya [45]
2 years ago
10

Billy Bob and Bob Bob are standing on a plank that is 9.0 m long and has mass 100 kg, that has supports at the 2 m and 5 m marks

. Billy Bob has mass 50 kg and is standing on the far left side, while Bob Bob has mass 90 kg and is walking toward the far right side. Will he make it all the way to the end without tipping the plank?

Physics
1 answer:
Liono4ka [1.6K]2 years ago
7 0

Answer:

No he will not make it all the way

Explanation:

In the attached figure we can see the plank will turn only of the turning moment will be greater than the restoring moment.

balancing moment is created by weight of the plank which acts at the center of the plank thus we have

taking moments about the support A we have

Balancing moment = M_{balancing}=100\times 2.5\times 9.81=2452.5Nm

The disturbing moment created by bob equals

M_{disturbing 1}=50\times 2\times 9.81=981Nm

The maximum disturbing moment created by bob occurs when he is at the far left side equaling

M_{disturbing 2}=90\times 2\times 9.81=1765.8Nm

Thus the maximum disturbing moment is sum of the above 2 moments

M_{max}=1765.8+981=2746.8Nm which is highly greater than the stabling  moment thus he will not make it.

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Answer:

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f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f

Where;

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v = The velocity of the sound wave

v_o = The velocity of the observer

v_s = The velocity of the source

Where the observer is stationary, we have;

(i) When the source is moving in the direction of the observer

f' = \left (\dfrac{v }{v - v_s} \right) \times f

(ii) When the source is receding from the observer, we have;

f' = \left (\dfrac{v }{v + v_s} \right) \times f

Therefore;

(a) A person left behind on the platform

For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

f' = \left (\dfrac{v }{v + v_s} \right) \times f

(1) Given that (v + v_s) > v, therefore, v < (v + v_s), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller

(b) A person down below floating on a rubber raft

For the the person down below on the rubber raft, the radio source is advancing

Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;

f' = \left (\dfrac{v }{v - v_s} \right) \times f

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(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

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Answer:

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Explanation:

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2 years ago
A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
PIT_PIT [208]

Their velocity afterward is  v=3.467 m/s

Explanation:

Given:

Mass of the first football player= 91.5 kg

Initial velocity of the football player 3.73 m/s

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Initial velocity of the second football player=3.09 m/s

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Final velocity of both players=?

Solution:

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Initial momentum =final momentum

mathematically represented as  

m_1u_1+m_2u_2=m_1v_1+m_2v_2...........................(1)

where

u_1=intial velocity of the football player

u_2 = inital velocity of second football player

v_1=finall velocity of the  first football player

v_2=final velocity of second football player

after tackling , both the football players moves with the same velocity,

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Hence equation (1) becomes

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}

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Answer:

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