Pls help me guys! Thanks =P

Mathematics

2 answers:

hichkok12 [17]3 years ago

8 0

I would just try to identify the pattern. First, for the cups column, if the amount increases by 5 each time, then the missing box must be 5 less than 10 or 5

The, for the servings column, you can test to find the pattern. If you were to guess the pattern is 3, when you check, you would see that the boxes are 6 and 9 because then it increases by 3 each time

Hope this helps

Rashid [163]3 years ago

5 0

To start with, you can see that the ratio of servings to cups by looking at the lowest row. 12 servings is 20 cups.
So you figure out what one serving is by dividing 20 cups by 12.
1 serve = 1.66 recurring cups, or 1 2/3.
So, multiply 1.66 by 3 to get the first space in the table:
3 servings is 5 cups.
So that makes the next one easy:
10 cups must be 6 servings.
15 cups would be 9 servings.

You can double check that by looking at the original pair that we started with. And yes, 12 servings is 20 cups fits right in iwth what we just did.

So now, just fill in the gaps in your grid.

You might be interested in

What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"

salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is $27 + 64x^{3}$

Now, the equation is $27 + 64x^{3} = 0$

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be $- \frac{3}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.

Again, we have to solve the difference of two cubes which is $64m^{3} - 1$

Now, the equation is $64m^{3} - 1 = 0$

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be $\frac{1}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation. (Answer)