Answer:
a. NaNO3 and CuCl2
Explanation:
The other 3 react as follows:
Ba(OH)2 and HNO3 ---> BaNO3 + H2O
CaCl2 + Na3PO4 ---> CaPO4 + NaCl
AgNO3 + HCl ---> AgCl + HNO3
Answer:
BaSO₄
Explanation:
Let's assume we have 100 g of the compound. If that's the case we would have:
Now we <u>convert the masses of each element into moles</u>, using their <em>respective molar masses</em>:
- 58.8 g Ba ÷ 137.327 g/mol = 0.428 mol Ba
- 13.74 g S ÷ 32 g/mol = 0.429 mol S
- 27.43 g O ÷ 16 g/mol = 1.71 mol O
We <u>divide those moles by the lowest number among them</u>:
We can express those results as Ba₁S₁O₄, meaning the empirical formula is thus BaSO₄.
Answer:
The range is also the whole of R
Explanation:
Answer:
Hope it helps.
Explanation:
It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131
