What is the mass of solute, in grams, in 250.00 mL of a 0.0125 M solution of KMnO4? Moles KMnO4 = M × V = 0.0125 M × 0.250 L = 3.13 × 10-3 mol KMnO4 grams KMnO4 = 3.13 × 10-3 mol KMnO4 × ( 158.03 g KMnO4/1 mol KMnO4) = 0.495 g 4.

8 0

3 years ago

9. How many grams of zinc are needed to produce 12 grams of zinc chloride according to the following equation? Y-

tensa zangetsu [6.8K]

Given :

A balanced chemical equation :

$Zn +Cl_2->ZnCl_2$

To Find :

How many grams of zinc are needed to produce 12 grams of zinc chloride.

Solution :

Moles of $ZnCl_2$ ,

$n=\dfrac{Given \ wt}{Molecular\ Mass}\\\\n =\dfrac{12}{136.30}\ mol\\\\n=0.088\ mol$

Now, by balanced chemical equation we can say that 1 mol of Zn produce

1 mol of $ZnCl_2$ .

So, 0.088 mol of Zn is required to produced 0.088 mol of $ZnCl_2$ .

$Mass \ required = molecular \ mass \times moles\\\\m = 65.38 \times 0.088\\\\m=5.8 \ gm$

Therefore, 5.8 grams of zinc is required.

Hence, this is the required solution.

4 0

3 years ago

How would you determine the proper number of significant figures for measurement of a liquid using a graduated cylinder?

Veronika [31]

You get ur answer
Ex: 4.5
And put a rounding number at the end/uncertain digit
Ex: 4.50

4 0

3 years ago

Which half-reaction is most easily reduced?

Morgarella [4.7K]

The answer is
<span>Fe3+ + e- Fe2+ = 0.77 V</span>

7 0

3 years ago

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