A calorimeter contains 500 g of water at 25°C.....
the temperature of the water inside the calorimeter is 39.4°C.....
The specific heat of water is 4.18 J/g-°C.
energy needed to heat the water = specific heat * mass * temp difference
= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)
= 4.18*500*14.4
= 30096J
or approx. 30kJ
Answer:
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Explanation:
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Explanation: