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3 years ago

Plzzzzzzzzzzz helpo friend

Chemistry

1 answer:

miv72 [106K]3 years ago

6 0

Answer:

They form volcanoes....

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Some kinds of matter are attracted to a magnet. Is this a physical or chemical property of matter?

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Liquid alcohol will change to vapor when its temperature reaches the

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Jenna is playing with her toy cars, which are both the same size. She pushes the red car with a strong push. She pushes the blue

Vikki [24]

Answer:

red car will travel a much farther distance and at a faster speed as opposed to the blue car

Explanation:

Based on the information provided within the question Jenna can expect to observe that the red car will travel a much farther distance and at a faster speed as opposed to the blue car which will travel a shorter distance and at a lower speed. This is mainly because Jenna is applying an increased amount of force on the red car thus creating more acceleration and ultimately increasing the distance.

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3 years ago

Consider the following reaction of the commercial production of SO3 using sulfur dioxide and oxygen: SO2(g) + O2(g) → SO3(g)

kipiarov [429]

Answer:

$m_{SO_3}=18.93gSO_3$

$V_{SO_3}=5.3LSO_3$

Explanation:

Hello,

STP conditions are P=1 atm and T=273.15 K, thus, the reacting moles are:

$n_{SO_2}=\frac{5.3L*1atm}{0.082\frac{atm*L}{mol*K}*273.15K}=0.2366molSO_2\\n_{O_2}=\frac{4.7L*1atm}{0.082\frac{atm*L}{mol*K}*273.15K}=0.2098molO_2$

Now, the balanced chemical reaction turns out into:

$2SO_2(g) + O_2(g) --> 2SO_3(g)$

Thus, the exact moles of oxygen that completely react with 0.2366 moles of sulfur dioxide are (limiting reagent identification):

$0.2366molSO_2*\frac{1molO_2}{2molSO_2}=0.1182molO_2$

Since 0.2098 moles of oxygen are available, we stipulate the oxygen is in excess and the sulfur dioxide is the limiting reagent. In such a way, the yielded grams of sulfur trioxide turn out into:

$m_{SO_3}=0.2366molSO_2*\frac{2molSO_3}{2molSO_2}*\frac{80gSO_3}{1molSO_3} \\m_{SO_3}=18.93gSO_3$

By using the ideal gas equation, one computes the volume as:

$V_{SO_3}=\frac{mRT}{MP}=\frac{18.93g*0.082\frac{atm*L}{mol*K} *273.15K}{80g/mol*1atm}\\V_{SO_3}=5.3LSO_3$

It has sense for volume since the mole ratio is 2/2 between sulfur dioxide and sulfur trioxide.

Best regards.

6 0

3 years ago