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lana [24]
3 years ago
14

Given ????(a1, aa2), ????(????1, ????2), ????(c1, c2), and ????(d1, d2), find a general formula in terms of a1, a2, ????1, ????2

, c1, c2, d1, and
d2 that will let us determine whether AB and CD are perpendicular.
Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

cant help when you put question marks!

please do this better!

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use the guide to construct a two column proof proving △aec≅△deb, given that ca is parallel to db and e is the midpoint of ad. gi
MrMuchimi

By using the AAA congruence property of Triangles, △aec≅△deb is proved

It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad

Also, it is given that,

ca ║db

We need to prove that, △aec≅△deb

Then we'll use AAA congruence property of Triangles to prove the situation

As ca ║db

then, ∠cae = ∠ebd  (Alternate angles)

∠ace = ∠edb (Alternate angles)

and ∠aec = ∠deb (common angles)

Thus, by AAA congruence property, △aec≅△deb

Hence, proved

To learn more about, congruence property, here

brainly.com/question/2039214

#SPJ4

5 0
1 year ago
A class of 40 students elected a class president. There were 12 votes for Candidate A, and 18 votes for Candidate B. The rest of
mote1985 [20]
40  students
12-A
18-B 
40-12=28
28-18=10
10/40 did not vote.
25% did not vote
10 is one fourth of 40
fourth of 100% is 25%
7 0
3 years ago
Show your work<br> −17x = −204
pishuonlain [190]
You would divide -204 divide it by -17 and you would get 12
X=12
6 0
3 years ago
Gabriel used 1/3 of a litter of milk to make 1/9 of jug of tea
MrRissso [65]
So he used 0.33 L of milk to make 0.11 L of tea
5 0
3 years ago
How do I do this? 50 points, please answer
xz_007 [3.2K]

Check the picture below.

now, the midsegment of a triangle, besides being half the base, we have to bear in mind that is a "mid" segment, is a segment that lies half-way along the segments it touches.

so for the triangle above, well, the midsegment DE is cutting the segment BC it two equal halves, BE and EC, that means that \stackrel{x}{BE}~~ = ~~\stackrel{8}{EC}.

5 0
1 year ago
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