Answer:
answer is of left to right
16x^14/(36x^2)=4x^12/9
(3^3)×(x^5)×y÷4
-9a^3(b^5)
Answer:
Step-by-step explanation:
Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.
Suppose that one employee is selected at random from a list of the employees
A) Probability that the selected employee has been with the firm less than 5 years = 
B) Probability that the selected employee has been with the firm between 5 and 10 years
= 
C) Probability that the selected employee has been with the firm more than 10 years
= 
a) P(A) = 0.2
P(C) = 0.5
P(A or B) = 0.2+0.3 = 0.5
P(A and C) = 0 (since A and C are disjoint)
Answer:
10 units
Step-by-step explanation:
We are given that
BD=x+29
AD=x+39
AC=20
BC=x+19
AC=AB+BC
20=AB+x+19
AB=20-x-19=1-x
AD=AB+BD


Substitute the value of x=-9
Then , we get BC=
units
Answer: BC=10 units