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2 years ago

Which expression has a sum of 1 2/21

Mathematics

1 answer:

mr_godi [17]2 years ago

5 0

Answer:

A. is the answer

Step-by-step explanation:

the LCM of 7 and 3 is 21.

When added it would be 9+14 =23

23/21= 1 2/21

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The legs of a right triangle have the following measurements: 5 and 10 inches. What is the length of the hypotenuse??

RideAnS [48]

Answer:

$5\sqrt{5}$

Step-by-step explanation:

1. $5^2 + 10^2 = c^2$

2. $125 = c^2$

3. $c=5\sqrt{5}$

7 0

2 years ago

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are:

$\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\ \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Answer: Third option

8 0

1 year ago

Let the sample be 11, 3, 4, 3, 5, 7, 8, 12. What is the range of the sample?

grin007 [14]

Solution

- The Range of a dataset is simply the difference between the largest number and the smallest number in the dataset.

- In the dataset given, the largest number is 12 while the smallest number is 3.

- Thus, the Range of the dataset is

$12-3=9$

Range = 9

7 0

9 months ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

3 0

3 years ago

Read 2 more answers

What is the end behavior of the graph?

hichkok12 [17]

Imagine that this curve is a roller coaster. A dot on the roller coaster would be a car for a person to sit in, so to speak. As this car moves to the right, the car ultimately moves downward. So this means that as x gets larger, y gets smaller. Put another way: as x approaches infinity, f(x) approaches negative infinity.

Similarly, we can move the other way to work our way to the left. Moving to the left has us go up this time. As x approaches negative infinity, f(x) approaches positive infinity

These two facts point to choice B as the final answer

8 0

2 years ago

Which￼ expression has a sum of￼ 1 2/21

Which expression has a sum of 1 2/21