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Anon25 [30]
3 years ago
8

Divide 657/3 using partial quotients

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
<span>657/3=219 is the easy way out but thats not what is being asked here so 100*6+57/3=219</span>
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What 18% more than 200
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Answer: 236

Explanation:

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3 years ago
Can you please help me with 23 and 25 I do not understand!!! Please help
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when you multiply a number by a value that's greater than 1, that number increases, for example 2 and then we multiply it like 2 * 3, clearly 2*3 is greater than 2.

now when you multiply a number  by a value that's lesser than 1, that number decreases, for example 2 and then we multiply it by something like 1/4, so 2 * 1/4 = 1/2, well, clearly 1/2 is smaller than 2, so 1/2 is a decreased value of 2.

23)

we have here 4/7, and then a product, well, the product is 4/7 and 9/10, however 9/10 is less than 1, recall 1 = 10/10, 9/10 is just a tiny bit less than 1.

because we're multiplying 4/7 by some amount less than 1, the product is a smaller value than 4/7, thus

 \bf \cfrac{4}{7}~~>~\left( \cfrac{9}{10}\times \cfrac{4}{7} \right)

25)

we have here 5/6 and we multiply it by 7/7, wait a minute!!! 7/7 = 1, we're really just multiplying 5/6 by 1 then, what does that give us?  well, 5/6 * 1  = 5/6, just the number itself,

\bf \cfrac{5}{6}~~=~\left( \cfrac{5}{6}\times \cfrac{7}{7} \right)

7 0
2 years ago
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Ierofanga [76]

Answer:

Step-by-step explanation:The probability of picking the biased coin: P(biased coin)=1/100. The probability of all three tosses is heads: P(three heads)=1×1+99×18100. The probability of three heads given the biased coin is trivial: P(three heads|biased coin)=1.

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3 years ago
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