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3 years ago

Can you help me please?

Mathematics

1 answer:

Snezhnost [94]3 years ago

5 0

Answer: A. TRUE

Step-by-step explanation:

For this exercise it is important to know that, by definition, a relation is a function if and only if each Input value has one and only one Outuput value.

In this case, you can observe in the picture attached, that:

1. The Input value $0$ has an unique Output value, which is $0$ .

2. The Input value $4$ has an unique Output value, which is $1$ .

3. The Input value $8$ has an unique Output value, which is $2$ .

4. The Input value $12$ has an unique Output value, which is $3$ .

Therefore, based on the definition shown at the beginning of this explanation, since each Input value of f(x) has only one output value, you can conclude that the f(x) is a function.

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A(3,4) and B(-3,2) are pointd on a coordinate plane. find the coordinate of a points C on the x axis such that AC=BC

mr Goodwill [35]

Answer:

Step-by-step explanation:

Here's the game plan. In order to find a point on the x-axis that makes AC = BC, we need to find the midpoint of AB and the slope of AB. From there, we can find the equation of the line that is perpendicular to AB so we can then fit a 0 in for y and solve for x. This final coordinate will be the answer you're looking for. First and foremost, the midpoint of AB:

and

Now for the slope of AB:

and

So if the slope of AB is 1/3, then the slope of a line perpendicular to that line is -3. What we are finding now is the equation of the line perpendicular to AB and going through (0, 3):

and filling in:

y - 3 = -3(x - 0) and

y - 3 = -3x + 0 and

y - 3 = -3x so

y = -3x + 3. Filling in a 0 for y will give us the coordinate we want for the x-intercept (the point where this line goes through the x-axis):

0 = -3x + 3 and

-3 = -3x so

x = 1

The coordinate on the x-axis such that AC = BC is (1, 0)

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2 years ago

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2 years ago

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S = 2B + L. What do S, B, and L stand for?

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3 years ago

write an equation in slope intercept form for the line that passes through the point, and is perpendicular to the line y=-1/3x+9

aleksklad [387]

Answer:

Step-by-step explanation:

y=-1/3x+9

This is written in the format y=mx+b, where m is the slope and b the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the slope of the reference line, in this case -(1/3). The new slope is 3. equation is:

y = 3x + b

To find b, enter the given point, (-6,-2) and solve for b:

y = 3x + b

-2 = 3(-6) + b

-2 = -18 + b

b = 16

The full equation is y=3x + 18