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2 years ago

A board 6 ft 11 in long is cut from a board 10 ft 5 in long. Find the length of the remaining

Mathematics

1 answer:

gulaghasi [49]2 years ago

4 0

Answer:

3' 6" left

Step-by-step explanation:

6' 11" = 83"

10' 5" = 125"

125 - 83 = 42"

42" = 3' 6"

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Suppose you just received a shipment of ten televisions. two of the televisions are defective. if two televisions are randomly

amid [387]

Try this solution:

1. for probability of both televisions work:

$P_{2w}=\frac{C^2_8}{C^2_{10}}=\frac{7*8}{9*10}=0.6(2)$

2. for probability of at least on is defective (it means, the sum = one is defective and two are defective):

$P_{1d}=\frac{C^1_2C^1_8}{C^2_{10}}=\frac{4*8}{9*10}=0.3(5)$ - for P(1defective);

$P_{2d}=\frac{C^2_2}{C^2_{10}}=\frac{2}{9*10}=0.0(2)$ - for P(2defective);

totaly for at least one is defective:

$P_{at \ least \ 1 \ d}=P_{1d}+P_{2d}=\frac{16}{45} +\frac{1}{45} =0.3(7)$

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3 years ago

Help me and ill mark branilest for first person to answer CORRECTLY. A histogram is being made for the following list of data. I

kolezko [41]

So to put them in intervals of 5 you would have:
70-74
75-79
80-84
85-89
90-94
95-99
In these intervals you would have:
70-74: 72
75-79: 78
80-84: 81
85-89: 86, 86, 87
90-94: 92, 92, 92
95-99: 98

The second interval is 75-79 where there is only one number. Therefore the frequency will be 1.
The correct answer is A. Hope this helps! :)

5 0

2 years ago

Please help me. thanks.

Rama09 [41]

$~~~\text{Area of triangle} = \dfrac 12 \times \text{Base} \times \text{Height}\\\\\implies 10 = \dfrac 12 \times 5 \times w\\\\\implies w =\dfrac{20}5 \\\\\implies w = 4 ~cm$

8 0

2 years ago

Read 2 more answers

On the first day of the baseball tournament, Jessie scored 2 runs. On the second day, 4 runs. On the third day, 6 runs. If this

Ivanshal [37]

It is going by two. So the answer is 16.

5 0

3 years ago

in preparation for a party, brant is putting desserts onto platters. the chocolate cake is cut into 15 pieces and the cheesecake

marishachu [46]

Answer:

The greatest number of platters he can prepare is 3.

Step-by-step explanation:

Given : In preparation for a party, brant is putting desserts onto platters. the chocolate cake is cut into 15 pieces and the cheesecake is cut into 6 pieces. if he wants to prepare identical platters without having any cake left over.

To find : What is the greatest number of platters he can prepare?

Solution :

The greatest number of platters he can prepare is given by finding the GCF of 15 and 6.

Factoring the numbers,

$6=2\times 3$

$15=3\times 5$

The GCF is the greatest common factor.

$GCF(6,15)=3$

Therefore, the greatest number of platters he can prepare is 3.

8 0

2 years ago