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3 years ago

10

Find cos 0, where 0 is the angle shown. Give an exact value, not a decimal approximation.

1 answer:

marin [14]3 years ago

5 0

Answer:

cosθ = $\frac{5}{13}$

Step-by-step explanation:

This is a 5- 12- 13 right triangle then

cosθ = $\frac{adjacent}{hypotenuse}$ = $\frac{5}{13}$

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Answer:

The general relation about a geoemtric sequence is

$a_{n}=a_{1}r^{n-1}$

For the first sequence, we have

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Now, we use the same process for the second sequence.

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The second equation is

$1440=a_{1}r^{5-1}\\a_{1}=\frac{1440}{r^{4} }$

Now, we solve the following expression

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We solve for $r$

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Then

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$a_{n}=\frac{5}{72} \times (12)^{n-1}$

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