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Alja [10]
3 years ago
14

Im doing systems of equations and its 2x+2y=16

Mathematics
1 answer:
xeze [42]3 years ago
8 0

Answer:

x=3, y=5 This means the point would be (3,5)

Step-by-step explanation:

As I am unable to see your work, I am unable to tell you what you did wrong, but I hope you can notice what was wrong by comparing your work to mine

We are given the equations

2x+2y=16\\3x-y=4

The first thing we need to do is solve one of them for a variable and use substitution. I chose the second equation

3x-y=4\\\\y=3x-4

Now we can substitute in this equation for y

2x+2y=16\\\\2x+2(3x-4)=16\\\\2x+6x-8=16\\\\8x=24\\\\x=3

Now that we have the value for x, we can plug it into the second equation to easily find y.

y=3x-4\\\\y=3(3)-4\\\\y=9-4\\\\y=5

Finally, we can plug x and y into the first equation in order to check to make sure it works for the other equation

2x+2y=16\\\\2(3)+2(5)=16\\\\6+10=16\\\\16=16

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3 years ago
Wx+yz=bc , solve for z .
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8 0
3 years ago
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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=3, u'(0)= -4, v(0)= 2, v'(0)= -7. Find the value
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\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
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\\\\
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7 0
3 years ago
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3 0
3 years ago
Y=y = 2x -4 when x= 2
Dominik [7]
Y would equal 0. 2x2=4 and 4-4=0.
7 0
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