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nexus9112 [7]
3 years ago
9

Chris and Goffy ran from Newton to Boston at 15 km/h and 12 km/h respectively. They both started from Newton at 10:00 a.m. If Go

ffy reached Boston at 10:30 a.m., at what time did Chris reach Boston ?
Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0

Answer: Chris reached Boston at 10:24 a.m.

Explanation:

Since we have given that

Speed at which Chris ran from Newton to Boston = 15 km/h

Speed at which Goffy ran from Newton to Boston = 12 km/h

Time at which both started = 10:00 a.m.

Time at which Goffy reached Boston = 10:30 a.m.

That means Goffy takes half an hour to reach Boston,

so, Distance between Newton and Boston is given by

Speed \times Time\\\\=12\times \frac{1}{2}=6 \ km

So, Time taken by Chris to ran from Newton and Boston is given by

Time=\frac{Distance}{Speed}=\frac{6}{15}=\frac{2}{5}\times 60\ minutes=24\ minutes\\

So, Chris reached Boston at 10:24 a.m.

lakkis [162]3 years ago
4 0

The Answer is 10:24 am because...


Chris=15km per hour

Goffy=12km per hour


So Goffy took 30 minutes Boston=6km from Newton. So Chris took 24 minutes and he got to Boston at 10:24 am


Hope this Helps you!      :)

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Nadya [2.5K]

Answer: she would catch up with Tom in 1 hour.

Step-by-step explanation:

Let t represent the time it will take for Mary to catch up with Tom.

Tom leaves his boat from a dock and travels at a rate of 25 miles per hour.

Distance = speed × time

Distance travelled by Tom in t hours is

25 × t = 25t

Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. Converting 10 minutes to hours, it becomes 10/60 hour

Time spent by Mary is (t - 10/60) hours. If she travels at a rate of 30 miles per hour, it means that the distance that she would travel in

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5t = 5

t = 5/5 = 1 hour

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3 years ago
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The particular quadratic solution to the ODE is found as follows:

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\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

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