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4 years ago

I will mark you as most Brillance if you help me get this right!

Mathematics

1 answer:

elena55 [62]4 years ago

8 0

Answer:

15.2

Step-by-step explanation:

4/3 × π × radius3.

4/3 × π ×12square

4/3 × π ×36

15.2

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The arena set-up team’s work schedule is shown in the table below. Convert the minutes worked into hours.

Sladkaya [172]

Answer:

$Mike\ Chewer = 14\frac{1}{2}\ hr$

$Jennifer\ Glass = 3\frac{3}{4}\ hr$

$Fred\ Carlton = 1\frac{1}{4}\ hr$

$Amy\ Amaretto = 12\ hr$

Step-by-step explanation:

Given

$Mike\ Chewer = 870\ minutes$

$Jennifer\ Glass = 225\ minutes$

$Fred\ Carlton = 75\ minutes\\$

$Amy\ Amaretto = 720\ minutes$

Required

Convert to hours (in fraction)

To do this, we simply divide the time by 60

$Mike\ Chewer = 870\ minutes$

Divide by 60

$Mike\ Chewer = \frac{870}{60}\ hr$

$Mike\ Chewer = \frac{87}{6}\ hr$

Express as mixed numbers

$Mike\ Chewer = 14\frac{3}{6}\ hr$

Simplify

$Mike\ Chewer = 14\frac{1}{2}\ hr$

$Jennifer\ Glass = 225\ minutes$

Divide by 60

$Jennifer\ Glass = \frac{225}{60}\ hr$

Express as mixed numbers

$Jennifer\ Glass = 3\frac{45}{60}\ hr$

Simplify

$Jennifer\ Glass = 3\frac{3}{4}\ hr$

$Fred\ Carlton = 75\ minutes\\$

Divide by 60

$Fred\ Carlton = \frac{75}{60}\ hr$

Express as mixed numbers

$Fred\ Carlton = 1\frac{15}{60}\ hr$

Simplify

$Fred\ Carlton = 1\frac{1}{4}\ hr$

$Amy\ Amaretto = 720\ minutes$

Divide by 60

$Amy\ Amaretto = \frac{720}{60}\ hr$

$Amy\ Amaretto = 12\ hr$

3 0

3 years ago

Solve m/n =p-6 for n

Olegator [25]

M / n = p - 6
m = (p - 6) (n)
m / (p - 6) = n

5 0

3 years ago

Write an equation for the line of best fit

Mariana [72]

Hi the answer is y=mx+ b10

7 0

3 years ago

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true

Feliz [49]

Answer:

a) The 95% CI for the true average porosity is (4.51, 5.19).

b) The 98% CI for true average porosity is (4.11, 5.01)

c) A sample size of 15 is needed.

d) A sample size of 101 is needed.

Step-by-step explanation:

a. Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 20 specimens from the seam was 4.85.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{0.78}{\sqrt{20}} = 0.34$

The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.34 = 4.51

The upper end of the interval is the sample mean added to M. So it is 4.35 + 0.34 = 5.19

The 95% CI for the true average porosity is (4.51, 5.19).

b. Compute a 98% CI for true average porosity of another seam based on 16 specimens with a sample average of 4.56.

Following the same logic as a.

98% C.I., so $z = 2.327$

$M = 2.327*\frac{0.78}{\sqrt{16}} = 0.45$

4.56 - 0.45 = 4.11

4.56 + 0.45 = 5.01

The 98% CI for true average porosity is (4.11, 5.01)

c. How large a sample size is necessary if the width of the 95% interval is to be 0.40?

A sample size of n is needed.

n is found when M = 0.4.

95% C.I., so Z = 1.96.

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.4 = 1.96*\frac{0.78}{\sqrt{n}}$

$0.4\sqrt{n} = 1.96*0.78$

$\sqrt{n} = \frac{1.96*0.78}{0.4}$

$(\sqrt{n})^{2} = (\frac{1.96*0.78}{0.4})^{2}$

$n = 14.6$

Rounding up

A sample size of 15 is needed.

d. What sample size is necessary to estimate the true average porosity to within 0.2 with 99% confidence?

99% C.I., so z = 2.575

n when M = 0.2.

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.2 = 2.575*\frac{0.78}{\sqrt{n}}$

$0.2\sqrt{n} = 2.575*0.78$

$\sqrt{n} = \frac{2.575*0.78}{0.2}$

$(\sqrt{n})^{2} = (\frac{2.575*0.78}{0.2})^{2}$

$n = 100.85$

Rounding up

A sample size of 101 is needed.

8 0

4 years ago

Toan is building tables for the park Department. He needs 20 bolts for each table. If he has 60 bolts at his workplace and he ge

Ipatiy [6.2K]

It is 20 per table. He has 60 already but buys 300 more.

60+300=360

In order to find out how many tables he can make, you'll need to divide.

360/20=18.

In total, Toan can make 18 tables

8 0

3 years ago